[git] Remove local git tags that are no longer on the remote repository

We use tags in git as part of our deployment process. From time to time, we want to clean up these tags by removing them from our remote repository.

This is pretty straightforward. One user deletes the local tag and the remote tag in one set of commands. We have a little shell script that combines both steps.

The 2nd (3rd, 4th,...) user now has local tags that are no longer reflected on the remote.

I am looking for a command similar to git remote prune origin which cleans up locally tracking branches for which the remote branch has been deleted.

Alternatively, a simple command to list remote tags could be used to compare to the local tags returned via git tag -l.

This question is related to git git-tag

The answer is


From Git v1.7.8 to v1.8.5.6, you can use this:

git fetch <remote> --prune --tags

Update

This doesn't work on newer versions of git (starting with v1.9.0) because of commit e66ef7ae6f31f2. I don't really want to delete it though since it did work for some people.

As suggested by "Chad Juliano", with all Git version since v1.7.8, you can use the following command:

git fetch --prune <remote> +refs/tags/*:refs/tags/*

You may need to enclose the tags part with quotes (on Windows for example) to avoid wildcard expansion:

git fetch --prune <remote> "+refs/tags/*:refs/tags/*"

The same answer as @Richard W but for Windows (PowerShell)

git tag | foreach-object -process { git tag -d $_ }
git fetch -t

In new git version(like v2.26.2)

-P, --prune-tags Before fetching, remove any local tags that no longer exist on the remote if --prune is enabled. This option should be used more carefully, unlike --prune it will remove any local references (local tags) that have been created. This option is a shorthand for providing the explicit tag refspec along with --prune, see the discussion about that in its documentation.

So you would need run:

git fetch august --prune --prune-tags

I add the command to SourceTree as a Custom Action on my MacOS.


Setting Custom Actions by Sourcetree -> Preferences... -> Custom Actions


Script to run have to be the git path.

I use git fetch --prune --prune-tags origin to sync tags from remote to local.

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Git natively supports cleanup of local tags:

git fetch --tags --prune

This command pulls in the latest tags and removes all deleted tags.


TortoiseGit can compare tags now.

Left log is on remote, right is at local.

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Using the Compare tags feature of Sync dialog:

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Also see TortoiseGit issue 2973


I know I'm late to the party, but now there's a quick answer to this:

git fetch --prune --prune-tags # or just git fetch -p -P

Yes, it's now an option to fetch.

If you don't want to fetch, and just prune:

git remote prune origin

this is a good method:

git tag -l | xargs git tag -d && git fetch -t

Source: demisx.GitHub.io


Just added a git sync-local-tags command to pivotal_git_scripts Gem fork on GitHub:

https://github.com/kigster/git_scripts

Install the gem, then run "git sync-local-tags" in your repository to delete the local tags that do not exist on the remote.

Alternatively you can just install this script below and call it "git-sync-local-tags":


#!/usr/bin/env ruby

# Delete tags from the local Git repository, which are not found on 
# a remote origin
#
# Usage: git sync-local-tags [-n]
#        if -n is passed, just print the tag to be deleted, but do not 
#        actually delete it.
#
# Author: Konstantin Gredeskoul (http://tektastic.com)
#
#######################################################################

class TagSynchronizer
  def self.local_tags
    `git show-ref --tags | awk '{print $2}'`.split(/\n/)
  end

  def self.remote_tags
    `git ls-remote --tags origin | awk '{print $2}'`.split(/\n/)
  end

  def self.orphaned_tags
    self.local_tags - self.remote_tags
  end

  def self.remove_unused_tags(print_only = false)
    self.orphaned_tags.each do |ref|
      tag = ref.gsub /refs\/tags\//, ''
      puts "deleting local tag #{tag}"
      `git tag -d #{tag}` unless print_only
    end
  end
end

unless File.exists?(".git")
  puts "This doesn't look like a git repository."
  exit 1
end

print_only = ARGV.include?("-n")
TagSynchronizer.remove_unused_tags(print_only)

Show the difference between local and remote tags:

diff <(git tag | sort) <( git ls-remote --tags origin | cut -f2 | grep -v '\^' | sed 's#refs/tags/##' | sort)
  • git tag gives the list of local tags
  • git ls-remote --tags gives the list of full paths to remote tags
  • cut -f2 | grep -v '\^' | sed 's#refs/tags/##' parses out just the tag name from list of remote tag paths
  • Finally we sort each of the two lists and diff them

The lines starting with "< " are your local tags that are no longer in the remote repo. If they are few, you can remove them manually one by one, if they are many, you do more grep-ing and piping to automate it.


How about this - drop all local tags and then re-fetch? Considering your repo might contain submodules:

git submodule foreach --recursive  'git tag | xargs git tag -d'
(alternatively, "for i in `find .git  -type d -name '*tags*'`; do rm -f $i/*;  done")
git fetch -t
git submodule foreach --recursive git fetch -t

This is great question, I'd been wondering the same thing.

I didn't want to write a script so sought a different solution. The key is discovering that you can delete a tag locally, then use git fetch to "get it back" from the remote server. If the tag doesn't exist on the remote, then it will remain deleted.

Thus you need to type two lines in order:

git tag -l | xargs git tag -d
git fetch --tags

These:

  1. Delete all tags from the local repo. FWIW, xargs places each tag output by "tag -l" onto the command line for "tag -d". Without this, git won't delete anything because it doesn't read stdin (silly git).

  2. Fetch all active tags from the remote repo.

This even works a treat on Windows.


All versions of Git since v1.7.8 understand git fetch with a refspec, whereas since v1.9.0 the --tags option overrides the --prune option. For a general purpose solution, try this:

$ git --version
git version 2.1.3

$ git fetch --prune origin "+refs/tags/*:refs/tags/*"
From ssh://xxx
 x [deleted]         (none)     -> rel_test

For further reading on how the "--tags" with "--prune" behavior changed in Git v1.9.0, see: https://github.com/git/git/commit/e66ef7ae6f31f246dead62f574cc2acb75fd001c


If you only want those tags which exist on the remote, simply delete all your local tags:

$ git tag -d $(git tag)

And then fetch all the remote tags:

$ git fetch --tags

Looks like recentish versions of Git (I'm on git v2.20) allow one to simply say

git fetch --prune --prune-tags

Much cleaner!

https://git-scm.com/docs/git-fetch#_pruning

You can also configure git to always prune tags when fetching:

git config fetch.pruneTags true

If you only want to prune tags when fetching from a specific remote, you can use the remote.<remote>.pruneTags option. For example, to always prune tags when fetching from origin but not other remotes,

git config remote.origin.pruneTags true