c compile error ISO C forbids comparison between pointer and integer

Question

I am trying an example from Bjarne Stroustrup s C   book  third edition  While implementing a rather simple function  I get the following compile time error   error  ISO C   forbids comparison between pointer and integer   What could be causing this  Here is the code  The error is in the if line    include  lt iostream gt   include  lt string gt  using namespace std  bool accept         cout  lt  lt   Do you want to proceed  y or n   n       char answer      cin  gt  gt  answer      if  answer     y   return true      return false      Thanks

User · Answer

A string literal is delimited by quotation marks and is of type char* not char.

Example: "hello"

So when you compare a char to a char* you will get that same compiling error.

char c = 'c';
char *p = "hello";

if(c==p)//compiling error
{
}

To fix use a char literal which is delimited by single quotes.

Example: 'c'

User · Answer

You need the change those double quotation marks into singles  ie  if  answer     y   returns true   Here is some info on String Literals in C    http   msdn microsoft com en-us library 69ze775t 28VS 80 29 aspx

User · Answer

y  is a string array pointer   y  is a char integral type

User · Answer

You must remember to use single quotes for char constants  So use  if  answer     y   return true   Rather than  if  answer     y   return true   I tested this and it works

User · Answer

You have two ways to fix this  The preferred way is to use   string answer     instead of char   The other possible way to fix it is   if  answer     y          note single quotes instead of double  representing a char constant

[c++] c++ compile error: ISO C++ forbids comparison between pointer and integer

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