How to convert integer to char in C

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Just assign the int to a char variable   int i   65  char c   i  printf   c   c     prints A

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void main           int temp integer count 0 i cnd 0      char ascii 10   0       printf  enter a number        scanf   d   amp integer          if integer gt  gt 31                CONVERTING 2 s complement value to normal value            integer  integer 1           for temp integer temp  0 temp  10 count              ascii 0  0x2D       count         cnd 1              else      for temp integer temp  0 temp  10 count              for i count-1 temp integer i gt  cnd i--                  ascii i   temp 10  0x30          temp  10             printf   n count   d ascii  s   count ascii

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You can try atoi   library function  Also sscanf   and sprintf   would help   Here is a small example to show converting integer to character string   main       int i   247593    char str 10      sprintf str    d   i        Now str contains the integer as characters      Here for another Example   include  lt stdio h gt   int main void       char text      StringX      int digit     for  digit   0  digit  lt  10    digit             text 6    digit    0         puts text           return 0        my output String0 String1 String2 String3 String4 String5 String6 String7 String8 String9

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To convert int to char use   int a 8    char c a  0   printf   c  c           prints 8     To Convert char to int use   char c  5   int a c- 0   printf   d  a            prints 5

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To convert integer to char only 0 to 9 will be converted  As we know 0 s ASCII value is 48 so we have to add its value to the integer value to convert in into the desired character  hence  int i 5  char c   i  0

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A char in C is already a number  the character s ASCII code   no conversion required   If you want to convert a digit to the corresponding character  you can simply add  0    c   i   0     The  0  is a character in the ASCll table

[c] How to convert integer to char in C?

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