Java doesn't want you to make an array of HashMaps, but it will let you make an array of Objects. So, just write up a class declaration as a shell around your HashMap, and make an array of that class. This lets you store some extra data about the HashMaps if you so choose--which can be a benefit, given that you already have a somewhat complex data structure.
What this looks like:
private static someClass[] arr = new someClass[someNum];
and
public class someClass {
private static int dataFoo;
private static int dataBar;
private static HashMap<String, String> yourArray;
...
}
You can't have an array of a generic type. Use List
instead.
You can use something like this:
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class testHashes {
public static void main(String args[]){
Map<String,String> myMap1 = new HashMap<String, String>();
List<Map<String , String>> myMap = new ArrayList<Map<String,String>>();
myMap1.put("URL", "Val0");
myMap1.put("CRC", "Vla1");
myMap1.put("SIZE", "Val2");
myMap1.put("PROGRESS", "Val3");
myMap.add(0,myMap1);
myMap.add(1,myMap1);
for (Map<String, String> map : myMap) {
System.out.println(map.get("URL"));
System.out.println(map.get("CRC"));
System.out.println(map.get("SIZE"));
System.out.println(map.get("PROGRESS"));
}
//System.out.println(myMap);
}
}
The Java Language Specification, section 15.10, states:
An array creation expression creates an object that is a new array whose elements are of the type specified by the PrimitiveType or ClassOrInterfaceType. It is a compile-time error if the ClassOrInterfaceType does not denote a reifiable type (ยง4.7).
and
The rules above imply that the element type in an array creation expression cannot be a parameterized type, other than an unbounded wildcard.
The closest you can do is use an unchecked cast, either from the raw type, as you have done, or from an unbounded wildcard:
HashMap<String, String>[] responseArray = (Map<String, String>[]) new HashMap<?,?>[games.size()];
Your version is clearly better :-)
Source: Stackoverflow.com