send post xml file using curl command line

Question

How can I send post an xml file to a local server http   localhost 8080 using curl from the command line    What command should I use

User · Answer

You can use this command   curl -X POST --header  Content-Type  multipart form-data  --header  Accept  application json  --header  Authorization   lt  lt Removed gt  gt   -F file    home xxx Desktop customers json    API SERVER URL  -k

User · Answer

From the manpage  I believe these are the droids you are looking for      -F --form  lt name content gt        HTTP  This lets curl emulate a filled-in form in which a user has pressed the submit button  This causes curl to POST data using the Content-Type multipart form-data according to RFC2388  This enables uploading of binary files etc  To force the  content  part to be a file  prefix the file name with an   sign        Example  to send your password file to the server  where  password  is the name of the form-field to which  etc passwd will be the input        curl -F password   etc passwd www mypasswords com   So in your case  this would be something like curl -F file   some file on your local disk http   localhost 8080

User · Answer

You can using option --data with file   Write xml content to a file named is soap get xml and using curl command to send request      curl -X POST --header  Content-Type text xml charset UTF-8  --data  soap get xml your url

User · Answer

If that question is connected to your other Hudson questions use the command they provide   This way with XML from the command line     curl -X POST -d   lt run gt     lt  run gt     http   user pass myhost myport path of url   You need to change it a little bit to read from a file      curl -X POST -d  myfilename http   user pass myhost myport path of url   Read the manpage  following an abstract for -d Parameter      -d --data        HTTP  Sends the specified data in a   POST request to the HTTP server  in   the same way that a browser does when   a user has filled in an HTML form and   presses the submit button  This will   cause curl to pass the data to the   server using the content-type   application x-www-form-urlencoded    Compare to -F --form       -d --data is the same as --data-ascii  To post data purely binary  you should   instead use the --data-binary option    To URL-encode the value of a form   field you may use --data-urlencode       If any of these options is used more   than once on the same command line    the data pieces specified will be   merged together with a separating    amp -symbol  Thus  using  -d name daniel   -d skill lousy  would generate a post chunk that looks like    name daniel amp skill lousy        If you start the data with the letter      the rest should be a file name to   read the data from  or - if you want   curl to read the data from stdin  The   contents of the file must already be   URL-encoded  Multiple files can also   be specified  Posting data from a file   named  foobar  would thus be done with   --data  foobar

User · Answer

If you have multiple headers then you might want to use the following   curl -X POST --header  Content-Type application json  --header  X-Auth AuthKey  --data  hello json Your url

User · Answer

If you are using curl on Windows   curl -H  Content-Type  application xml  -d   lt  xml version    1 0    encoding    UTF-8    standalone    yes     gt  lt message gt  lt sender gt Me lt  sender gt  lt content gt Hello  lt  content gt  lt  message gt   http   localhost 8080 webapp rest hello

User · Answer

Here s how you can POST XML on Windows using curl command line on Windows  Better use batch  cmd file for that   curl -i -X POST -H  Content-Type  text xml  -d                  lt  xml version   1 0   encoding   UTF-8      gt                         lt Transaction  gt                                                        lt SomeParam1  gt Some-Param-01  lt  SomeParam1  gt                         lt Password  gt SomePassW0rd  lt  Password  gt                              lt Transaction Type  gt 00  lt  Transaction Type  gt                        lt CardHoldersName  gt John Smith  lt  CardHoldersName  gt                  lt DollarAmount  gt 9 97  lt  DollarAmount  gt                              lt Card Number  gt 4111111111111111  lt  Card Number  gt                    lt Expiry Date  gt 1118  lt  Expiry Date  gt                                lt VerificationStr2  gt 123  lt  VerificationStr2  gt                       lt CVD Presence Ind  gt 1  lt  CVD Presence Ind  gt                         lt Reference No  gt Some Reference Text  lt  Reference No  gt               lt Client Email  gt john smith com  lt  Client Email  gt                    lt Client IP  gt 123 4 56 7  lt  Client IP  gt                              lt Tax1Amount  gt   lt  Tax1Amount  gt                                      lt Tax2Amount  gt   lt  Tax2Amount  gt                                  lt  Transaction  gt                                                http   localhost 8080

User · Answer

With Jenkins 1 494  I was able to send a file to a job parameter on Ubuntu Linux 12 10 using curl with --form parameters   curl --form name myfileparam --form file   local path to your file xml     -Fjson    parameter     name    myfileparam    file    file         -Fsubmit Build     http   user password jenkinsserver job jobname build   On the Jenkins server  I configured a job that accepts a single parameter  a file upload parameter named myfileparam   The first line of that curl call constructs a web form with a parameter named myfileparam  same as in the job   its value will be the contents of a file on the local file system named  local path to your file txt  The   symbol prefix tells curl to send a local file instead of the given filename   The second line defines a JSON request that matches the form parameters on line one  a file parameter named myfileparam   The third line activates the form s Build button  The forth line is the job URL with the   build  suffix   If this call is successful  curl returns 0  If it is unsuccessful  the error or exception from the service is printed to the console  This answer takes a lot from an old blog post relating to Hudson  which I deconstructed and re-worked for my own needs

User · Answer

Powershell   Curl   Zimbra SOAP API   my xml      quot   lt  xml version   quot 1 0  quot  encoding   quot UTF-8  quot   gt   lt soapenv Envelope xmlns soapenv   quot http   schemas xmlsoap org soap envelope   quot  gt     lt soapenv Body gt      lt GetFolderRequest xmlns   quot urn zimbraMail  quot  gt       lt folder gt          lt path gt Folder Name lt  path gt       lt  folder gt      lt  GetFolderRequest gt     lt  soapenv Body gt   lt  soapenv Envelope gt   quot      my curl     quot c  curl exe quot    cookie     quot c  cookie txt quot     zimbra soap url     quot https   zimbra 7071 service admin soap quot    curl getfolder args     quot -b quot    quot   cookie  quot                quot --header quot    quot Content-Type  text xml charset UTF-8 quot                quot --silent quot                quot --data-raw quot    quot   my xml  quot                quot --url quot    quot   zimbra soap url  quot    xml   my response     amp    my curl    curl getfolder args    my response  Envelope Body GetFolderResponse folder id

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