How do I get the path to the current script with Node js

Question

How would I get the path to the script in Node js   I know there s process cwd  but that only refers to the directory where the script was called  not of the script itself  For instance  say I m in  home kyle  and I run the following command   node  home kyle some dir file js   If I call process cwd    I get  home kyle   not  home kyle some dir    Is there a way to get that directory

User · Answer

Use   dirname      dirname   The directory name of the current module  This the same as the path dirname   of the   filename   Example  running node example js from  Users mjr  console log   dirname      Prints   Users mjr console log path dirname   filename       Prints   Users mjr   https   nodejs org api modules html modules dirname  For ESModules you would want to use  import meta url

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I found it after looking through the documentation again  What I was looking for were the   filename and   dirname module-level variables      filename is the file name of the current module  This is the resolved absolute path of the current module file   ex  home kyle some dir file js    dirname is the directory name of the current module   ex  home kyle some dir

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This command returns the current directory   var currentPath   process cwd      For example  to use the path to read the file   var fs   require  fs    fs readFile process cwd        text txt   function err  data        if err          console log err      else         console log data toString

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var settings        JSON parse          require  fs   readFileSync              require  path   resolve                    dirname                    settings json                 utf8

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When it comes to the main script it s as simple as  process argv 1   From the Node js documentation   process argv An array containing the command line arguments  The first element will be  node   the second element will be the path to the JavaScript file  The next elements will be any additional command line arguments   If you need to know the path of a module file then use   filename

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If you want something more like  0 in a shell script  try this   var path   require  path     var command   getCurrentScriptPath     console log  Usage    command   lt foo gt   lt bar gt      function getCurrentScriptPath             Relative path from current working directory to the location of this script     var pathToScript   path relative process cwd      filename           Check if current working dir is the same as the script     if  process cwd         dirname               E g     foobar js          return       path sep   pathToScript        else              E g   foo bar baz js          return pathToScript

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Use the basename method of the path module   var path   require  path    var filename   path basename   filename   console log filename     Here is the documentation the above example is taken from   As Dan pointed out  Node is working on ECMAScript modules with the  --experimental-modules  flag   Node 12 still supports   dirname and   filename as above     If you are using the --experimental-modules flag  there is an alternative approach   The alternative is to get the path to the current ES module   const   filename   new URL import meta url  pathname    And for the directory containing the current module   import path from  path    const   dirname   path dirname new URL import meta url  pathname

User · Answer

So basically you can do this   fs readFile path resolve   dirname   settings json     UTF-8   callback     Use resolve   instead of concatenating with     or     else you will run into cross-platform issues   Note    dirname is the local path of the module or included script  If you are writing a plugin which needs to know the path of the main script it is   require main filename   or  to just get the folder name   require  path   dirname require main filename

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Every Node js program has some global variables in its environment  which represents some information about your process and one of it is   dirname

User · Answer

I know this is pretty old  and the original question I was responding to is marked as duplicate and directed here  but I ran into an issue trying to get jasmine-reporters to work and didn t like the idea that I had to downgrade in order for it to work  I found out that jasmine-reporters wasn t resolving the savePath correctly and was actually putting the reports folder output in jasmine-reporters directory instead of the root directory of where I ran gulp  In order to make this work correctly I ended up using process env INIT CWD to get the initial Current Working Directory which should be the directory where you ran gulp  Hope this helps someone    var reporters   require  jasmine-reporters    var junitReporter   new reporters JUnitXmlReporter     savePath  process env INIT CWD     report e2e      consolidateAll  true    captureStdout  true

User · Answer

index js within any folder containing modules to export const entries       for  const aFile of require  fs   readdirSync   dirname    withFileTypes  true    filter ent   gt  ent isFile    amp  amp  ent name      index js        const   name  suffix     aFile name split         entries name    require      aFile name        module exports   entries   This will find all files in the root of the current directory  require and export every file present with the same export name as the filename stem

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Node js 10 supports ECMAScript modules  where   dirname and   filename are no longer available   Then to get the path to the current ES module one has to use   import   fileURLToPath   from  url    const   filename   fileURLToPath import meta url     And for the directory containing the current module   import   dirname   from  path   import   fileURLToPath   from  url    const   dirname   dirname fileURLToPath import meta url

User · Answer

You can use process env PWD to get the current app folder path

User · Answer

If you are using pkg to package your app  you ll find useful this expression   appDirectory   require  path   dirname process pkg   process execPath    require main   require main filename   process argv 0        process pkg tells if the app has been packaged by pkg   process execPath holds the full path of the executable  which is  usr bin node or similar for direct invocations of scripts  node test js   or the packaged app  require main filename holds the full path of the main script  but it s empty when Node runs in interactive mode    dirname holds the full path of the current script  so I m not using it  although it may be what OP asks  then better use appDirectory   process pkg   require  path   dirname process execPath       dirname    require  path   dirname process argv 0     noting that in interactive mode   dirname is empty  For interactive mode  use either process argv 0  to get the path to the Node executable or process cwd   to get the current directory

[node.js] How do I get the path to the current script with Node.js?

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