Get line number while using grep

Question

I am using grep recursive to search files for a string  and all the matched files and the lines containing that string are print on the terminal  But is it possible to get the line numbers of those lines too    ex  presently what I get is  var www file php   options    this target   but what I am trying to get is  var www file php  1142  options    this target    well where 1142 would be the line number containing that string   Syntax I am using to grep recursively is sudo grep -r  pattern    var www file php   One more question is  how do we get results for not equal to a pattern  Like all the files but not the ones having a certain string

User · Answer

In order to display the results with the line numbers, you might try this

grep -nr "word to search for" /path/to/file/file

The result should be something like this:

linenumber: other data "word to search for" other data

User · Answer

grep -A20 -B20 pattern file txt   Search pattern and show 20 lines after and before pattern

User · Answer

If you want only the line number do this  grep -n Pattern file ext   gawk   print  1   FS  quot   quot   Example    grep -n 9780545460262 EXT20130410 txt   gawk   print  1   FS  quot   quot   48793 52285 54023

User · Answer

grep -nr  search string  directory  This gives you the line with the line number

User · Answer

Line numbers are printed with grep -n   grep -n pattern file txt   To get only the line number  without the matching line   one may use cut   grep -n pattern file txt   cut -d   -f 1   Lines not containing a pattern are printed with grep -v   grep -v pattern file txt

User · Answer

grep -n SEARCHTERM file1 file2

[grep] Get line number while using grep

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