[python] Check if space is in a string

' ' in word == True

I'm writing a program that checks whether the string is a single word. Why doesn't this work and is there any better way to check if a string has no spaces/is a single word..

You can try this, and if it will find any space it will return the position where the first space is.

if mystring.find(' ') != -1:
    print True
else:
    print False

word = ' '
while True:
    if ' ' in word:
        word = raw_input("Please enter a single word: ")
    else:
        print "Thanks"
        break

This is more idiomatic python - comparison against True or False is not necessary - just use the value returned by the expression ' ' in word.

Also, you don't need to use pastebin for such a small snippet of code - just copy the code into your post and use the little 1s and 0s button to make your code look like code.

def word_in(s):
   return " " not in s 

You can see whether the output of the following code is 0 or not.

'import re
x='  beer   '
len(re.findall('\s', x))

You can say word.strip(" ") to remove any leading/trailing spaces from the string - you should do that before your if statement. That way if someone enters input such as " test " your program will still work.

That said, if " " in word: will determine if a string contains any spaces. If that does not working, can you please provide more information?

Use this:

word = raw_input("Please enter a single word : ")
while True:
    if " " in word:
        word = raw_input("Please enter a single word : ")
    else:
        print "Thanks"
        break

# The following would be a very simple solution.

print("")
string = input("Enter your string :")
noofspacesinstring = 0
for counter in string:
    if counter == " ":
       noofspacesinstring += 1
if noofspacesinstring == 0:
   message = "Your string is a single word" 
else:
   message = "Your string is not a single word"
print("")   
print(message)   
print("")

You can use the 're' module in Python 3.
If you indeed do, use this:

re.search('\s', word)

This should return either 'true' if there's a match, or 'false' if there isn't any.

There are a lot of ways to do that :

t = s.split(" ")
if len(t) > 1:
  print "several tokens"

To be sure it matches every kind of space, you can use re module :

import re
if re.search(r"\s", your_string):
  print "several words"

Write if " " in word: instead of if " " in word == True:.

Explanation:

• In Python, for example a < b < c is equivalent to (a < b) and (b < c).
• The same holds for any chain of comparison operators, which include in!
• Therefore ' ' in w == True is equivalent to (' ' in w) and (w == True) which is not what you want.