[python] SQLAlchemy equivalent to SQL "LIKE" statement

A tags column has values like "apple banana orange" and "strawberry banana lemon". I want to find the SQLAlchemy equivalent statement to

SELECT * FROM table WHERE tags LIKE "%banana%";

What should I pass to Class.query.filter() to do this?

Using PostgreSQL like (see accepted answer above) somehow didn't work for me although cases matched, but ilike (case insensisitive like) does.

Adding to the above answer, whoever looks for a solution, you can also try 'match' operator instead of 'like'. Do not want to be biased but it perfectly worked for me in Postgresql.

Note.query.filter(Note.message.match("%somestr%")).all()

It inherits database functions such as CONTAINS and MATCH. However, it is not available in SQLite.

For more info go Common Filter Operators

try this code

output = dbsession.query(<model_class>).filter(<model_calss>.email.ilike('%' + < email > + '%'))

If you use native sql, you can refer to my code, otherwise just ignore my answer.

SELECT * FROM table WHERE tags LIKE "%banana%";

from sqlalchemy import text

bar_tags = "banana"

# '%' attention to spaces
query_sql = """SELECT * FROM table WHERE tags LIKE '%' :bar_tags '%'"""

# db is sqlalchemy session object
tags_res_list = db.execute(text(query_sql), {"bar_tags": bar_tags}).fetchall()