I am working on a webapplication comprises UI-Angular , Server-Java , RestEasy 3.0.9.Final for rest api calls
When i tried to access the rest service from another domain am getting below error
CANNOT LOAD Response to preflight request doesn't pass access control check: No 'Access-Control-Allow-Origin' header is present on the requested resource. Origin 'http://localhost:8080' is therefore not allowed access.
I configured my server side to respond with the cross domain calls and this is working with the GET Call but POST Call is creating ERROR
web.xml
<context-param>
<param-name>resteasy.providers</param-name>
<param-value>com.test.sample.app.CorsFeature</param-value>
</context-param>
<listener>
<listener-class>
org.jboss.resteasy.plugins.server.servlet.ResteasyBootstrap</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>resteasy-servlet</servlet-name>
<servlet-class>
org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher</servlet-class>
<init-param>
<param-name>javax.ws.rs.Application</param-name>
<param-value>com.test.sample.app.Application</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>resteasy-servlet</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
<context-param>
<param-name>resteasy.servlet.mapping.prefix</param-name>
<param-value>/rest</param-value>
</context-param>
<context-param>
<param-name>resteasy.scan</param-name>
<param-value>true</param-value>
</context-param>
Service class
@GET
@Path("/getnameAtt")
@Produces(MediaType.APPLICATION_JSON)
public Response getHostnameAttributes() {
return Response
.status(200)
.header("Access-Control-Allow-Origin", "*")
.header("Access-Control-Allow-Headers",
"origin, content-type, accept, authorization")
.header("Access-Control-Allow-Credentials", "true")
.header("Access-Control-Allow-Methods",
"GET, POST, PUT, DELETE, OPTIONS, HEAD")
.header("Access-Control-Max-Age", "1209600")
.entity(new TestImpl().getHostNameAttributes())
.build();
}
@POST
@Path("/getSeq")
@Produces(MediaType.APPLICATION_JSON)
public Response getCurrentSequence(String request) {
return Response
.status(200)
.header("Access-Control-Allow-Origin", "*")
.header("Access-Control-Allow-Headers",
"origin, content-type, accept, authorization")
.header("Access-Control-Allow-Credentials", "true")
.header("Access-Control-Allow-Methods",
"GET, POST, PUT, DELETE, OPTIONS, HEAD")
.header("Access-Control-Max-Age", "1209600")
.entity(new TestImpl().getCurrentSeq(request))
.build();
}
Since i am new to resteasy not able to figure out why this was not working. Any help would be greatly appreciated . Waiting for your response.
Thanks
After facing a similar issue, below is what I did :
To the CORS filter, I added corsFilter.getAllowedOrigins().add("http://localhost:4200");
.
Basically, you should add the URL which you want to allow Cross-Origin Resource Sharing. Ans you can also use "*"
instead of any specific URL to allow any URL.
public class RestApplication
extends Application
{
private Set<Object> singletons = new HashSet<Object>();
public MessageApplication()
{
singletons.add(new CalculatorService()); //CalculatorService is your specific service you want to add/use.
CorsFilter corsFilter = new CorsFilter();
// To allow all origins for CORS add following, otherwise add only specific urls.
// corsFilter.getAllowedOrigins().add("*");
System.out.println("To only allow restrcited urls ");
corsFilter.getAllowedOrigins().add("http://localhost:4200");
singletons = new LinkedHashSet<Object>();
singletons.add(corsFilter);
}
@Override
public Set<Object> getSingletons()
{
return singletons;
}
}
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>Restful Web Application</display-name>
<!-- Auto scan rest service -->
<context-param>
<param-name>resteasy.scan</param-name>
<param-value>true</param-value>
</context-param>
<context-param>
<param-name>resteasy.servlet.mapping.prefix</param-name>
<param-value>/rest</param-value>
</context-param>
<listener>
<listener-class>
org.jboss.resteasy.plugins.server.servlet.ResteasyBootstrap
</listener-class>
</listener>
<servlet>
<servlet-name>resteasy-servlet</servlet-name>
<servlet-class>
org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher
</servlet-class>
<init-param>
<param-name>javax.ws.rs.Application</param-name>
<param-value>com.app.RestApplication</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>resteasy-servlet</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
The most important code which I was missing when I was getting this issue was, I was not adding my class extending javax.ws.rs.Application i.e RestApplication to the init-param of <servlet-name>resteasy-servlet</servlet-name>
<init-param>
<param-name>javax.ws.rs.Application</param-name>
<param-value>com.app.RestApplication</param-value>
</init-param>
And therefore my Filter was not able to execute and thus the application was not allowing CORS from the URL specified.
Seems your resource POST
method won't get hit as @peeskillet mention. Most probably your ~POST~ request won't work, because it may not be a simple request. The only simple requests are GET, HEAD or POST and request headers are simple(The only simple headers are Accept, Accept-Language, Content-Language, Content-Type= application/x-www-form-urlencoded, multipart/form-data, text/plain).
Since in you already add Access-Control-Allow-Origin
headers to your Response, you can add new OPTIONS
method to your resource class.
@OPTIONS
@Path("{path : .*}")
public Response options() {
return Response.ok("")
.header("Access-Control-Allow-Origin", "*")
.header("Access-Control-Allow-Headers", "origin, content-type, accept, authorization")
.header("Access-Control-Allow-Methods", "GET, POST, PUT, DELETE, OPTIONS, HEAD")
.header("Access-Control-Max-Age", "2000")
.build();
}
Source: Stackoverflow.com