My version:
while '' in all_lines:
all_lines.pop(all_lines.index(''))
If you are not willing to try regex (which you should), you can use this:
s.replace('\n\n','\n')
Repeat this several times to make sure there is no blank line left. Or chaining the commands:
s.replace('\n\n','\n').replace('\n\n','\n')
Just to encourage you to use regex, here are two introductory videos that I find intuitive:
• Regular Expressions (Regex) Tutorial
• Python Tutorial: re Module
lines = bigstring.split('\n')
lines = [line for line in lines if line.strip()]
I also tried regexp and list solutions, and list one is faster.
Here is my solution (by previous answers):
text = "\n".join([ll.rstrip() for ll in original_text.splitlines() if ll.strip()])
you can simply use rstrip:
for stuff in largestring:
print(stuff.rstrip("\n")
Surprised a multiline re.sub has not been suggested (Oh, because you've already split your string... But why?):
>>> import re
>>> a = "Foo\n \nBar\nBaz\n\n Garply\n \n"
>>> print a
Foo
Bar
Baz
Garply
>>> print(re.sub(r'\n\s*\n','\n',a,re.MULTILINE))
Foo
Bar
Baz
Garply
>>>
Try list comprehension and string.strip()
:
>>> mystr = "L1\nL2\n\nL3\nL4\n \n\nL5"
>>> mystr.split('\n')
['L1', 'L2', '', 'L3', 'L4', ' ', '', 'L5']
>>> [line for line in mystr.split('\n') if line.strip() != '']
['L1', 'L2', 'L3', 'L4', 'L5']
I use this solution to delete empty lines and join everything together as one line:
match_p = re.sub(r'\s{2}', '', my_txt) # my_txt is text above
Same as what @NullUserException said, this is how I write it:
removedWhitespce = re.sub(r'^\s*$', '', line)
Source: Stackoverflow.com