[windows] How to get the path of the batch script in Windows?

I know that %0 contains the full path of the batch script, e.g. c:\path\to\my\file\abc.bat

I would path to be equal to c:\path\to\my\file

How could I achieve that ?

%~dp0 may be a relative path. To convert it to a full path, try something like this:

pushd %~dp0
set script_dir=%CD%
popd

That would be the %CD% variable.

@echo off
echo %CD%

%CD% returns the current directory the batch script is in.

%~dp0 - return the path from where script executed

But, important to know also below one:

%CD% - return the current path in runtime, for example if you get into other folders using "cd folder1", and then "cd folder2", it will return the full path until folder2 and not the original path where script located

I am working on a Windows 7 machine and I have ended up using the lines below to get the absolute folder path for my bash script.

I got to this solution after looking at http://www.linuxjournal.com/content/bash-parameter-expansion.

#Get the full aboslute filename.
filename=$0
#Remove everything after \. An extra \ seems to be necessary to escape something...
folder="${filename%\\*}"
#Echo...
echo $filename
echo $folder

You can use %~dp0, d means the drive only, p means the path only, 0 is the argument for the full filename of the batch file.

For example if the file path was C:\Users\Oliver\Desktop\example.bat then the argument would equal C:\Users\Oliver\Desktop\, also you can use the command set cpath=%~dp0 && set cpath=%cpath:~0,-1% and use the %cpath% variable to remove the trailing slash.

You can use following script to get the path without trailing "\"

for %%i in ("%~dp0.") do SET "mypath=%%~fi"

%cd% will give you the path of the directory from where the script is running.

Just run:

echo %cd%