[python] not None test in Python

The best bet with these types of questions is to see exactly what python does. The dis module is incredibly informative:

>>> import dis
>>> dis.dis("val != None")
  1           0 LOAD_NAME                0 (val)
              2 LOAD_CONST               0 (None)
              4 COMPARE_OP               3 (!=)
              6 RETURN_VALUE
>>> dis.dis("not (val is None)")
  1           0 LOAD_NAME                0 (val)
              2 LOAD_CONST               0 (None)
              4 COMPARE_OP               9 (is not)
              6 RETURN_VALUE
>>> dis.dis("val is not None")
  1           0 LOAD_NAME                0 (val)
              2 LOAD_CONST               0 (None)
              4 COMPARE_OP               9 (is not)
              6 RETURN_VALUE

Notice that the last two cases reduce to the same sequence of operations, Python reads not (val is None) and uses the is not operator. The first uses the != operator when comparing with None.

As pointed out by other answers, using != when comparing with None is a bad idea.