[javascript] jQuery: value.attr is not a function

I have this snipped in my page:

$('#category_sorting_form_save').click(function(){
    var elements = $("#category_sorting_elements > div");
    $.each(elements, function(key, value) {
        console.info(key," : ",value);
        console.info("cat_id: ",value.attr('cat_id'));
    });
});

And when it is executed, I get:

0 : <div class="dragable" cat_id="6" value="" style="opacity: 1;">    
value.attr is not a function
    console.info("cat_id: ",value.attr('cat_id'));

What am I doing wrong here? I am trying to get the value of the div.cat_id element.

This question is related to javascript jquery

The answer is


The second parameter of the callback function passed to each() will contain the actual DOM element and not a jQuery wrapper object. You can call the getAttribute() method of the element:

$('#category_sorting_form_save').click(function() {
    var elements = $("#category_sorting_elements > div");
    $.each(elements, function(key, value) {
        console.info(key, ": ", value);
        console.info("cat_id: ", value.getAttribute('cat_id'));
    });
});

Or wrap the element in a jQuery object yourself:

$('#category_sorting_form_save').click(function() {
    var elements = $("#category_sorting_elements > div");
    $.each(elements, function(key, value) {
        console.info(key, ": ", value);
        console.info("cat_id: ", $(value).attr('cat_id'));
    });
});

Or simply use $(this):

$('#category_sorting_form_save').click(function() {
    var elements = $("#category_sorting_elements > div");
    $.each(elements, function() {
        console.info("cat_id: ", $(this).attr('cat_id'));
    });
});

You can also use jQuery('.class-name').attr("href"), in my case it works better.

Here more information: "jQuery(...)" instead of "$(...)"


You are dealing with the raw DOM element .. need to wrap it in a jquery object

console.info("cat_id: ",$(value).attr('cat_id'));