Initialize a string in C to empty string

Question

I want to initialize string in C to empty string  I tried   string 0           but it wrote   warning  assignment makes integer from pointer without a cast    How should I do it then

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To achieve this you can use   strcpy string

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You want to set the first character of the string to zero  like this   char myString 10   myString 0      0      Or myString 0    0    Or  actually  on initialisation  you can do   char myString 10          But that s not a general way to set a string to zero length once it s been defined

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Assuming your array called  string  already exists  try  string 0      0      0 is the explicit NUL terminator  required to mark the end of string

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I think Amarghosh answered correctly  If you want to Initialize an empty string without knowing the size  the best way is     this will create an empty string without no memory allocation   char str         it is look like  0    But if you want initialize a string with a fixed memory allocation you can do      this is better if you know your string size      char str 5         it is look like  0  0  0  0  0

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Assigning string literals to char array is allowed only during declaration   char string           This declares string as a char array of size 1 and initializes it with  0   Try this too   char str1          char str2 5         printf   d   d n   sizeof str1   sizeof str2      prints 1  5

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It s a bit late but I think your issue may be that you ve created a zero-length array  rather than an array of length 1    A string is a series of characters followed by a string terminator    0    An empty string      consists of no characters followed by a single string terminator character - i e  one character in total   So I would try the following   string 1        Note that this behaviour is not the emulated by strlen  which does not count the terminator as part of the string length

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string 0           warning  assignment makes integer from pointer without a cast  Ok  let s dive into the expression      0 an int  represents the number of chars  assuming string is  or decayed into  a char   to advance from the beginning of the object string  string 0   the char object located at the beginning of the object string      string literal  an object of type char 1      assignment operator  tries to assign a value of type char 1  to an object of type char  char 1   decayed to char   and char are not assignment compatible  but the compiler trusts you  the programmer  and goes ahead with the assignment anyway by casting the type char   what char 1  decayed to  to an int --- and you get the warning as a bonus  You have a really nice compiler  -

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calloc allocates the requested memory and returns a pointer to it  It also sets allocated memory to zero   In case you are planning to use your string as empty string all the time   char  string   NULL  string    char  calloc 1  sizeof char      In case you are planning to store some value in your string later   char  string   NULL  int numberOfChars   50     you can use as many as you need string    char  calloc numberOfChars   1  sizeof char

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In addition to Will Dean s version  the following are common for whole buffer initialization   char s 10       0      or  char s 10   memset s    0   sizeof s      or  char s 10   strncpy s      sizeof s

[c] Initialize a string in C to empty string

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