[javascript] type checking in javascript

A clean approach

You can consider using a very small, dependency-free library like Not. Solves all problems:

// at the basic level it supports primitives
let number = 10
let array = []
not('number', 10) // returns false
not('number', []) // throws error

// so you need to define your own:
let not = Object.create(Not)

not.defineType({
    primitive: 'number',
    type: 'integer',
    pass: function(candidate) {
        // pre-ECMA6
        return candidate.toFixed(0) === candidate.toString()
        // ECMA6
        return Number.isInteger(candidate)
    }
})
not.not('integer', 4.4) // gives error message
not.is('integer', 4.4) // returns false
not.is('integer', 8) // returns true

If you make it a habit, your code will be much stronger. Typescript solves part of the problem but doesn't work at runtime, which is also important.

function test (string, boolean) {
    // any of these below will throw errors to protect you
    not('string', string)
    not('boolean', boolean)

    // continue with your code.
}