Check if a number is int or float

Question

Here s how I did it   inNumber   somenumber inNumberint   int inNumber  if inNumber    inNumberint      print  this number is an int  else      print  this number is a float    Something like that  Are there any nicer looking ways to do this

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pls check this  import numbers  import math  a   1 1 - 0 1 print a   print isinstance a  numbers Integral  print math floor  a   if  math floor  a      a       print  It is an integer number  else      print False   Although X is float but the value is integer  so if you want to check the value is integer you cannot use isinstance and you need to compare values not types

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Here s a piece of code that checks whether a number is an integer or not  it works for both Python 2 and Python 3   import sys  if sys version  lt   3       integer types    int  long   else      integer types    int    isinstance yourNumber  integer types     returns True if it s an integer isinstance yourNumber  float     returns True if it s a float   Notice that Python 2 has both types int and long  while Python 3 has only type int  Source   If you want to check whether your number is a float that represents an int  do this   isinstance yourNumber  float  and  yourNumber  is integer       True for 3 0   If you don t need to distinguish between int and float  and are ok with either  then ninjagecko s answer is the way to go  import numbers  isinstance yourNumber  numbers Real

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def is int x     absolute   abs x    rounded   round absolute    if absolute - rounded    0      print str x      is an integer    else      print str x     is not an integer    is int 7 0    will print 7 0 is an integer

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What you can do too is usingtype   Example   if type inNumber     int   print  This number is an int  elif type inNumber     float   print  This number is a float

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One-liner   isinstance yourNumber  numbers Real    This avoids some problems    gt  gt  gt  isinstance 99  10 int  False   Demo    gt  gt  gt  import numbers   gt  gt  gt  someInt   10  gt  gt  gt  someLongInt   100000L  gt  gt  gt  someFloat   0 5   gt  gt  gt  isinstance someInt  numbers Real  True  gt  gt  gt  isinstance someLongInt  numbers Real  True  gt  gt  gt  isinstance someFloat  numbers Real  True

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You can do it with simple if statement To check for float if type a   type 1 1  To check for integer type if type a   type 1

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Tried in Python version 3 6 3 Shell   gt  gt  gt  x   12  gt  gt  gt  import numbers  gt  gt  gt  isinstance x  numbers Integral  True  gt  gt  gt  isinstance x int  True   Couldn t figure out anything to work for

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I know it s an old thread but this is something that I m using and I thought it might help   It works in python 2 7 and python 3 lt     def is float num               Checks whether a number is float or integer      Args          num float or int   The number to check      Returns          True if the number is float             return not  float num   is integer     class TestIsFloat unittest TestCase       def test float self           self assertTrue is float 2 2        def test int self           self assertFalse is float 2

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absolute   abs x  rounded   round absolute  if absolute - rounded    0    print  Integer number  else    print  notInteger number

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Update  Try this   inNumber    32  12 5   e   82  52  92   1224 5    12 53               10000 000   10 000459                This is a sentance  with comma number 1 and dot     121 124    try       def find float num           num   num split              if num -1  is not None and num -1  isdigit                return True         else              return False      for i in inNumber          i   str i  replace                   if     in i and find float i               print  This is float   i          elif i isnumeric                print  This is an integer   i          else              print  This is not a number     i   except Exception as err      print err

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Use isinstance    gt  gt  gt  x   12  gt  gt  gt  isinstance x  int  True  gt  gt  gt  y   12 0  gt  gt  gt  isinstance y  float  True   So    gt  gt  gt  if isinstance x  int           print  x is a int    x is a int     EDIT    As pointed out  in case of long integers  the above won t work  So you need to do    gt  gt  gt  x   12L  gt  gt  gt  import numbers  gt  gt  gt  isinstance x  numbers Integral  True  gt  gt  gt  isinstance x  int  False

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I like  ninjagecko s answer the most   This would also work      for Python 2 x    isinstance n   int  long  float         Python 3 x doesn t have long    isinstance n   int  float     there is also type complex for complex numbers

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You can use modulo to determine if x is an integer numerically  The isinstance x  int  method only determines if x is an integer by type   def isInt x       if x 1    0          print  X is an integer      else          print  X is not an integer

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Try this     def is int x     absolute   abs x    rounded   round absolute    return absolute - rounded    0

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variable isnumeric checks if a value is an integer    if myVariable isnumeric      print  this varibale is numeric    else      print  not numeric

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Use the most basic of type inference that python has   gt  gt  gt    Float Check  gt  gt  gt  myNumber   2 56  gt  gt  gt  print type myNumber     int  False  gt  gt  gt  print type myNumber     float  True  gt  gt  gt  print type myNumber     bool  False  gt  gt  gt   gt  gt  gt    Integer Check  gt  gt  gt  myNumber   2  gt  gt  gt  print type myNumber     int  True  gt  gt  gt  print type myNumber     float  False  gt  gt  gt  print type myNumber     bool  False  gt  gt  gt   gt  gt  gt    Boolean Check  gt  gt  gt  myNumber   False  gt  gt  gt  print type myNumber     int  False  gt  gt  gt  print type myNumber     float  False  gt  gt  gt  print type myNumber     bool  True  gt  gt  gt   Easiest and Most Resilient Approach in my Opinion

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It s easier to ask forgiveness than ask permission   Simply perform the operation   If it works  the object was of an acceptable  suitable  proper type   If the operation doesn t work  the object was not of a suitable type   Knowing the type rarely helps     Simply attempt the operation and see if it works   inNumber   somenumber try      inNumberint   int inNumber      print  this number is an int  except ValueError      pass try      inNumberfloat   float inNumber      print  this number is a float  except ValueError      pass

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how about this solution    if type x  in  float  int         do whatever else        do whatever

[python] Check if a number is int or float

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