Return list of items in list greater than some value

Question

I have the following list  j  4 5 6 7 1 3 7 5    What s the simplest way to return  5 5 6 7 7  being the elements in j greater or equal to 5

User · Answer

You can use a list comprehension    x for x in j if x  gt   5

User · Answer

Since your desired output is sorted  you also need to sort it    gt  gt  gt  j  4  5  6  7  1  3  7  5   gt  gt  gt  sorted x for x in j if x  gt   5   5  5  6  7  7

User · Answer

A list comprehension is a simple approach   j2    x for x in j if x  gt   5    Alternately  you can use filter for the exact same result   j2   filter lambda x  x  gt   5  j    Note that the original list j is unmodified

User · Answer

You can use a list comprehension to filter it   j2    i for i in j if i  gt   5    If you actually want it sorted like your example was  you can use sorted   j2   sorted i for i in j if i  gt   5    or call sort on the final list   j2    i for i in j if i  gt   5  j2 sort

User · Answer

Use filter  short version without doing a function with lambda  using   le     j2   filter  5    le    j   Example  python 3    gt  gt  gt  j  4 5 6 7 1 3 7 5   gt  gt  gt  j2   filter  5    le    j   gt  gt  gt  j2  lt filter object at 0x000000955D16DC18 gt   gt  gt  gt  list j2   5  6  7  7  5   gt  gt  gt    Example  python 2    gt  gt  gt  j  4 5 6 7 1 3 7 5   gt  gt  gt  j2   filter  5    le    j   gt  gt  gt  j2  5  6  7  7  5   gt  gt  gt   Use   le   i recommend this  it s very easy    le   is your friend If want to sort it to desired output  both versions    gt  gt  gt  j  4 5 6 7 1 3 7 5   gt  gt  gt  j2   filter  5    le    j   gt  gt  gt  sorted j2   5  5  6  7  7   gt  gt  gt    Use sorted Timings   gt  gt  gt  from timeit import timeit  gt  gt  gt  timeit lambda   i for i in j if i  gt   5     Michael Mrozek 1 4558496298222325  gt  gt  gt  timeit lambda  filter lambda x  x  gt   5  j     Justin Ardini 0 693048732089828  gt  gt  gt  timeit lambda  filter  5    le    j     Mine 0 714461565831428  gt  gt  gt    So Justin wins   With number 1   gt  gt  gt  from timeit import timeit  gt  gt  gt  timeit lambda   i for i in j if i  gt   5  number 1    Michael Mrozek 1 642193421957927e-05  gt  gt  gt  timeit lambda  filter lambda x  x  gt   5  j  number 1    Justin Ardini 3 421236300482633e-06  gt  gt  gt  timeit lambda  filter  5    le    j  number 1    Mine 1 8474676011237534e-05  gt  gt  gt    So Michael wins    gt  gt  gt  from timeit import timeit  gt  gt  gt  timeit lambda   i for i in j if i  gt   5  number 10    Michael Mrozek 4 721306089550126e-05  gt  gt  gt  timeit lambda  filter lambda x  x  gt   5  j  number 10    Justin Ardini 1 0947956184281793e-05  gt  gt  gt  timeit lambda  filter  5    le    j  number 10    Mine 1 5053439710754901e-05  gt  gt  gt    So Justin wins again

User · Answer

In case you are considering using the numpy module  it makes this task very simple  as requested   import numpy as np  j   np array  4  5  6  7  1  3  7  5    j2   np sort j j  gt   5     The code inside of the brackets  j  gt   5  produces a list of True or False values  which then serve as indices to select the desired values in j  Finally  we sort with the sort function built into numpy   Tested result  a numpy array    array  5  5  6  7  7

User · Answer

There is another way    j3   j2  gt  4  print j2 j3     tested in 3 x

[python] Return list of items in list greater than some value

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