I am receiving this error in Python 3.5.1.
json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)
Here is my code:
import json
import urllib.request
connection = urllib.request.urlopen('http://python-data.dr-chuck.net/comments_220996.json')
js = connection.read()
print(js)
info = json.loads(str(js))
This question is related to
json
python-3.x
The answer is
If you look at the output you receive from print() and also in your Traceback, you'll see the value you get back is not a string, it's a bytes object (prefixed by b):
b'{\n "note":"This file .....
If you fetch the URL using a tool such as curl -v, you will see that the content type is
Content-Type: application/json; charset=utf-8
So it's JSON, encoded as UTF-8, and Python is considering it a byte stream, not a simple string. In order to parse this, you need to convert it into a string first.
Change the last line of code to this:
info = json.loads(js.decode("utf-8"))
in my case, some characters like " , :"'{}[] " maybe corrupt the JSON format, so use try json.loads(str) except to check your input
Source: Stackoverflow.com