[javascript] jQuery - multiple $(document).ready ...?

It is important to note that each jQuery() call must actually return. If an exception is thrown in one, subsequent (unrelated) calls will never be executed.

This applies regardless of syntax. You can use jQuery(), jQuery(function() {}), $(document).ready(), whatever you like, the behavior is the same. If an early one fails, subsequent blocks will never be run.

This was a problem for me when using 3rd-party libraries. One library was throwing an exception, and subsequent libraries never initialized anything.