Python - Check If Word Is In A String

Question

I m working with Python v2  and I m trying to find out if you can tell if a word is in a string   I have found some information about identifying if the word is in the string - using  find  but is there a way to do an IF statement  I would like to have something like the following   if string find word       print  success    Thanks for any help

User · Answer

This small function compares all search words in given text. If all search words are found in text, returns length of search, or False otherwise.

Also supports unicode string search.

def find_words(text, search):
    """Find exact words"""
    dText   = text.split()
    dSearch = search.split()

    found_word = 0

    for text_word in dText:
        for search_word in dSearch:
            if search_word == text_word:
                found_word += 1

    if found_word == len(dSearch):
        return lenSearch
    else:
        return False

usage:

find_words('çelik güray ankara', 'güray ankara')

User · Answer

Advanced way to check the exact word  that we need to find in a long string   import re text    This text was of edited by Rock   try this string also  text    This text was officially edited by Rock   for m in re finditer r  bof b   text       if m group 0           print  Present      else          print  Absent

User · Answer

You can split string to the words and check the result list   if word in string split        print  success

User · Answer

if  seek  in  those who seek shall find       print  Success      but keep in mind that this matches a sequence of characters  not necessarily a whole word - for example   word  in  swordsmith  is True  If you only want to match whole words  you ought to use regular expressions   import re  def findWholeWord w       return re compile r  b  0   b  format w   flags re IGNORECASE  search  findWholeWord  seek    those who seek shall find        - gt   lt match object gt  findWholeWord  word    swordsmith                       - gt  None

User · Answer

If you want to find out whether a whole word is in a space-separated list of words  simply use   def contains word s  w       return        w        in        s         contains word  the quick brown fox    brown      True contains word  the quick brown fox    row        False   This elegant method is also the fastest  Compared to Hugh Bothwell s and daSong s approaches    gt python -m timeit -s  def contains word s  w   return        w        in        s          contains word  the quick brown fox    brown    1000000 loops  best of 3  0 351 usec per loop   gt python -m timeit -s  import re  -s  def contains word s  w   return re compile r  b  0   b  format w   flags re IGNORECASE  search s    contains word  the quick brown fox    brown    100000 loops  best of 3  2 38 usec per loop   gt python -m timeit -s  def contains word s  w   return s startswith w        or s endswith       w  or s find       w           -1   contains word  the quick brown fox    brown    1000000 loops  best of 3  1 13 usec per loop   Edit  A slight variant on this idea for Python 3 6   equally fast   def contains word s  w       return f   w    in f   s

User · Answer

What is wrong with   if word in mystring      print  success

User · Answer

You could just add a space before and after  word    x   raw input  Type your word     if   word   in x      print  Yes  elif   word   not in x      print  Nope    This way it looks for the space before and after  word     gt  gt  gt  Type your word  Swordsmith  gt  gt  gt  Nope  gt  gt  gt  Type your word   word   gt  gt  gt  Yes

User · Answer

Using regex is a solution  but it is too complicated for that case   You can simply split text into list of words  Use split separator  num  method for that  It returns a list of all the words in the string  using separator as the separator  If separator is unspecified it splits on all whitespace  optionally you can limit the number of splits to num    list of words   mystring split   if word in list of words      print  success    This will not work for string with commas etc  For example   mystring    One two and three    will split into   One two    and    three     If you also want to split on all commas etc  use separator argument like this     whitespace chars      t n r f  - space  tab  newline  return  formfeed list of words   mystring split   t n r f             if word in list of words      print  success

User · Answer

As you are asking for a word and not for a string  I would like to present a solution which is not sensitive to prefixes   suffixes and ignores case      usr bin env python  import re   def is word in text word  text               Check if a word is in a text       Parameters     ----------     word   str     text   str      Returns     -------     bool   True if word is in text  otherwise False       Examples     --------      gt  gt  gt  is word in text  Python    python is awesome        True       gt  gt  gt  is word in text  Python    camelCase is pythonic        False       gt  gt  gt  is word in text  Python    At the end is Python       True             pattern   r       w        w      format word      pattern   re compile pattern  re IGNORECASE      matches   re search pattern  text      return bool matches    if   name         main         import doctest     doctest testmod     If your words might contain regex special chars  such as     then you need re escape word

User · Answer

What about to split the string and strip words punctuation  w in  ws strip         for ws in p split     Or working the case  w lower   in  ws strip         for ws in p lower   split     Maybe that way  def wsearch word  phrase         Attention about punctuation and about split characters     punctuation              return word lower   in  words strip punctuation  for words in phrase lower   split     Sample  print wsearch  CAr    I own a caR      I didn t check performance

User · Answer

find returns an integer representing the index of where the search item was found   If it isn t found  it returns -1   haystack    asdf   haystack find  a     result  0 haystack find  s     result  1 haystack find  g     result  -1  if haystack find needle   gt   0    print  Needle found   else    print  Needle not found

User · Answer

If matching a sequence of characters is not sufficient and you need to match whole words  here is a simple function that gets the job done  It basically appends spaces where necessary and searches for that in the string   def smart find haystack  needle       if haystack startswith needle               return True     if haystack endswith     needle           return True     if haystack find     needle         -1          return True     return False   This assumes that commas and other punctuations have already been stripped out

[python] Python - Check If Word Is In A String

Examples related to python

Examples related to string