[sql] SQL grouping by month and year

I'm not sure what should I write in the following SQL query to show 'date' column like this: "month-year" - "9-2011".

SELECT MONTH(date) + '.' + YEAR(date) AS Mjesec, SUM(marketingExpense) AS SumaMarketing, SUM(revenue) AS SumaZarada 
FROM [Order]
WHERE (idCustomer = 1) AND (date BETWEEN '2001-11-3' AND '2011-11-3')
GROUP BY MONTH(date), YEAR(date)

So, what I want to do is to change the data from the first column to show month and year instead of showing month only.

This question is related to sql sql-server

The answer is


If you want to stay having the field in datetime datatype, try using this:

SELECT DATEADD(MONTH, DATEDIFF(MONTH, 0, o.[date]), 0) AS Mjesec, SUM(marketingExpense) AS SumaMarketing, SUM(revenue) AS SumaZarada 
FROM [Order] o
WHERE (idCustomer = 1) AND (o.[date] BETWEEN '2001-11-3' AND '2011-11-3')
GROUP BY DATEADD(MONTH, DATEDIFF(MONTH, 0, o.[date]), 0)

It it also easy to change to group by hours, days, weeks, years...
I hope it is of use to someone,

Regards!


In postgresql I can write a similar query with a date-format function (to_char) and grouping just by date:

SELECT to_char (datum, 'MM-YYYY') AS mjesec 
FROM test 
GROUP BY datum 
ORDER BY datum;

Such thing is surely possible with SQL-Server too, isn't it?


For mariaDB you can:

SELECT DATE_FORMAT(date, '%m-%Y')
FROM [Order]
GROUP BY 
DATE_FORMAT(date, '%m-%Y')

Link: https://mariadb.com/kb/en/library/date_format/


I guess is MS SQL as it looks like MS SQL syntax.

So you should put in the group line the same thing as in select ex:

Select MONTH(date)+'-'+YEAR(date), ....
...
...
...
group by MONTH(date)+'-'+YEAR(date)

Yet another alternative: 

Select FORMAT(date,'MM.yy')
...
...
group by FORMAT(date,'MM.yy')

You can try multiplication to adjust the year and month so they will be one number. This, from my tests, runs much faster than format(date,'yyyy.MM'). I prefer having the year before month for sorting purpose. Code created from MS SQL Server Express Version 12.0.

SELECT (YEAR(Date) * 100) + MONTH(Date) AS yyyyMM
FROM [Order]
...
GROUP BY (YEAR(Date) * 100) + MONTH(Date)
ORDER BY yyyyMM

SQL Server 2012 above, I prefer use format() function, more simplify.

SELECT format(date,'MM.yyyy') AS Mjesec, SUM(marketingExpense) AS SumaMarketing, SUM(revenue) AS SumaZarada 
FROM [Order]
WHERE (idCustomer = 1) AND (date BETWEEN '2001-11-3' AND '2011-11-3')
GROUP BY format(date,'MM.yyyy')

If I understand correctly. In order to group your results as requested, your Group By clause needs to have the same expression as your select statement.

GROUP BY MONTH(date) + '.' + YEAR(date)

To display the date as "month-date" format change the '.' to '-' The full syntax would be something like this.

SELECT MONTH(date) + '-' + YEAR(date) AS Mjesec, SUM(marketingExpense) AS
SumaMarketing, SUM(revenue) AS SumaZarada 
FROM [Order]
WHERE (idCustomer = 1) AND (date BETWEEN '2001-11-3' AND '2011-11-3')
GROUP BY MONTH(date) + '.' + YEAR(date)