How to remove the character at a given index from a string in C

Question

How do I remove a character from a string     If I have the string  abcdef  and I want to remove  b  how do I do that   Removing the first character is easy with this code    include  lt stdio h gt   include  lt stdlib h gt   include  lt string h gt   int main        char word      abcdef      char word2 10       strcpy word2  amp word 1        printf   s n   word2       return 0      and  strncpy word2 word strlen word -1     will give me the string without the last character  but I still didn t figure out how to remove a char in the middle of a string

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My way to remove all specified chars   void RemoveChars char  s  char c        int writer   0  reader   0       while  s reader                 if  s reader   c                            s writer      s reader                      reader                      s writer  0

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This might be one of the fastest ones  if you pass the index   void removeChar char  str  unsigned int index        char  src      for  src   str index   src      0    src     src 1    src         src     0

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A convenient  simple and fast way to get rid of  0 is to copy the string without the last char   0  with the help of strncpy instead of strcpy   strncpy newStrg oldStrg  strlen oldStrg -1

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include  lt stdio h gt   include  lt stdlib h gt   include  lt string h gt   define MAX 50 void dele char char s   char ch        int i j       for i 0 s i     0  i                  if s i   ch                        for j i s j     0  j                s j  s j 1               i--                     int main         char s MAX  ch      printf  Enter the string n        gets s       printf  Enter The char to be deleted n        scanf   c   amp ch       dele char s ch       printf  After Deletion    s n  s       return 0

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Another solution  using memmove   along with index   and sizeof     char buf 100     abcdef   char remove    b    char  c  if   c   index buf  remove      NULL        size t len left   sizeof buf  -  c 1-buf       memmove c  c 1  len left       buf   now contains  acdef

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int chartoremove   1   strncpy word2  word  chartoremove   strncpy   char  word2  chartoremove    char  word  chartoremove 1      strlen word -1-chartoremove    Ugly as hell

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Edit    Updated the code zstring remove chr   according to the latest version of the library   From a BSD licensed string processing library for C  called zString  https   github com fnoyanisi zString  Function to remove a character  int zstring search chr char  token char s       if   token    s    0           return 0       for    token  token            if   token    s              return 1       return 0     char  zstring remove chr char  str const char  bad        char  src   str    dst   str          validate input        if    str  amp  amp  bad           return NULL       while  src          if zstring search chr bad  src               src            else              dst      src        assign first  then incement          dst   0       return str      Exmaple Usage     char s    this is a trial string to test the function       char  d          printf   s n  zstring remove chr s d      Example Output    thisisatrialstringtotestthefunction

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Use strcat   to concatenate strings   But strcat   doesn t allow overlapping so you d need to create a new string to hold the output

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include  lt stdio h gt   include  lt string h gt   int main        char ch 15  ch1 15       int i      gets ch       the original string     for  i 0 i lt strlen ch  i               while  ch i   ch i 1                 strncpy ch1 ch i 1     ch1 contains all the characters up to and including x             ch1 i    0     removing x from ch1             strcpy ch  amp ch i 1        shrinking ch  removing all the characters up to and including x from ch             strcat ch1 ch     rejoining both parts             strcpy ch ch1     just wanna stay classy                     puts ch       Let s suppose that x is the  symbol  of the character you want to remove  my idea was to divide the string into 2 parts   1st part will countain all the characters from the index 0 till  and including  the target character x   2nd part countains all the characters after x  not including x   Now all you have to do is to rejoin both parts

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Following should do it    include  lt stdio h gt   include  lt string h gt   int main  int argc  char const  argv          char word      quot abcde quot       int i      int len   strlen word       int rem   1          remove rem th char from word        for  i   rem  i  lt  len - 1  i    word i    word i   1       if  i  lt  len  word i      0        printf  quot  s n quot   word       return 0

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Really surprised this hasn t been posted before   strcpy  amp str idx to delete    amp str idx to delete   1      Pretty efficient and simple  strcpy uses memmove on most implementations

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This is what you may be looking for while counter is the index    include  lt stdio h gt   int main         char str 20       int i counter      gets str       scanf   d    amp counter        for  i  counter 1  str i     0   i             str i-1  str i             str i-1  0      puts str          return 0

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This code will delete all characters that  you enter from string   include  lt stdio h gt   include  lt string h gt    define SIZE 1000  char  erase c char  p  int ch        char  ptr       while  ptr   strchr p  ch           strcpy ptr  ptr   1        return p     int main         char str SIZE       int ch       printf  Enter a string n        gets str       printf  Enter the character to delete n        ch   getchar         erase c str  ch        puts str        return 0      input   a man  a plan  a canal Panama   output   A mn   pln   cnl  Pnm

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I know that the question is very old  but I will leave my implementation here   char     ft strdelchr const char  str char c            int   i          int   j          char   s          char   newstr           i   0          j   0             cast to char  to be able to modify  bc the param is const            you guys can remove this and change the param too         s    char  str             malloc the new string with the necessary length              obs  strcountchr returns int number of c haracters  inside s tring          if    newstr   malloc ft strlen s  - ft strcountchr s  c    1   sizeof char                     return  NULL           while  s i                             if  s i     c                                            newstr j    s i                           j                                      i                      return  newstr       just throw to a new string the characters that are not equal to the character you want to remove

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Try this    void removeChar char  str  char garbage         char  src   dst      for  src   dst   str   src      0   src               dst    src          if   dst    garbage  dst               dst     0       Test program   int main void        char  str   malloc strlen  abcdef   1       strcpy str   abcdef        removeChar str   b        printf   s   str       free str       return 0      Result    gt  gt acdef

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The following will extends the problem a bit by removing from the first string argument any character that occurs in the second string argument         delete one character from a string     static void  strdelchr  char  s  size t i  size t  a  size t  b      size t        j     if   a     b       a   i - 1    else     for  j    b   1  j  lt  i  j          s     a     s j      b   i           delete all occurrences of characters in search from s    returns nr  of deleted characters     size t strdelstr  char  s  const char  search       size t        l                 strlen s     size t        n                 strlen search     size t        i    size t        a                 0    size t        b                 0     for  i   0  i  lt  l  i        if  memchr  search  s i   n          strdelchr  s  i   amp a   amp b      strdelchr  s  l   amp a   amp b     s   a      0     return l - a

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this is how I implemented the same in c      include  lt iostream gt   include  lt cstring gt   using namespace std   int leng  char ch  string str  cpy   int main         cout  lt  lt   Enter a string         getline cin  str       leng   str length        cout  lt  lt  endl  lt  lt   Enter the character to delete         cin  gt  gt  ch      for  int i 0  i lt leng  i              if  str i     ch          cpy    str i             cout  lt  lt  endl  lt  lt   String after removal     lt  lt  cpy      return 0

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char a    string   int toBeRemoved 2  memmove  amp a toBeRemoved   amp a toBeRemoved 1  strlen a -toBeRemoved   puts a     Try this   memmove will overlap it  Tested

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I tried with strncpy   and snprintf     int ridx   1    strncpy word2 word ridx      snprintf word2 ridx 10-ridx   s   amp word ridx 1

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memmove can handle overlapping areas  I would try something like that  not tested  maybe  -1 issue   char word      abcdef     int idxToDel   2   memmove  amp word idxToDel    amp word idxToDel   1   strlen word  - idxToDel     Before   abcdef   After   abdef

[c] How to remove the character at a given index from a string in C?

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