[windows] How to count no of lines in text file and store the value into a variable using batch script?

I want to count the no of lines in a text file and then the value has to be stored into a environment variable. The command to count the no of lines is

findstr /R /N "^" file.txt | find /C ":"

I refered the question How to store the result of a command expression in a variable using bat scripts? Then I tried,

set cmd="findstr /R /N "^" file.txt | find /C ":" "

I am getting the error message,

FIND: Parameter format not correct

How could i get rid of this error.

@Tony: You can even get rid of the type %file% command.

for /f "tokens=2 delims=:" %%a in ('find /c /v "" %_file%') do set /a _Lines=%%a

For long files this should be even quicker.

You can also mark with a wildcard symbol * to facilitate group files to count.

Z:\SQLData>find /c /v "" FR_OP133_OCCURENCES_COUNT_PER_DOCUMENTS_*.txt

Result

---------- FR_OP133_OCCURENCES_COUNT_PER_DOCUMENTS_AVIFRS01_V1.TXT: 2041

---------- FR_OP133_OCCURENCES_COUNT_PER_DOCUMENTS_AVIOST00_V1.TXT: 315938

---------- FR_OP133_OCCURENCES_COUNT_PER_DOCUMENTS_AVIFRS00_V1.TXT: 0

---------- FR_OP133_OCCURENCES_COUNT_PER_DOCUMENTS_CNTPTF00_V1.TXT: 277

One nice surprise is for one who has git bash on his windows: just plain old linux wc -l <filename> will works for you there

You don't need to use find.

@echo off
set /a counter=0
for /f %%a in (filename) do set /a counter+=1
echo Number of lines: %counter%

This iterates all lines in the file and increases the counter variable by 1 for each line.

There is a much simpler way than all of these other methods.

find /v /c "" filename.ext

Holdover from the legacy MS-DOS days, apparently. More info here: https://devblogs.microsoft.com/oldnewthing/20110825-00/?p=9803

Example use:

adb shell pm list packages | find /v /c ""

If your android device is connected to your PC and you have the android SDK on your path, this prints out the number of apps installed on your device.

The perfect solution is:

FOR /F %%i IN ('TYPE "Text file.txt" ^| FIND /C /V ""') DO SET Lines=%%i

I found this solution to work best for creating a log file that maintains itself:

setlocal enabledelayedexpansion
SET /A maxlines= 10
set "cmd=findstr /R /N "^^" "filename.txt" | find /C ":""
 for /f %%a in ('!cmd!') do set linecount=%%a
GOTO NEXT

:NEXT 
 FOR /F %%A IN ("filename.txt") DO ( 
  IF %linecount% GEQ %maxlines% GOTO ExitLoop
  echo %clientname% %Date% %Time% >> "filename.txt")
 EXIT

:ExitLoop
 echo %clientname% %Date% %Time% > "filename.txt"
 EXIT

Environmental variables included are %clientname% the computername of the remote client %Date% is the current date and %Time% the current time. :NEXT is called after getting the number of lines in the file. If the file line count is greater than the %maxlines% variable it goes to the :EXITLOOP where it overwrites the file, creating a new one with the first line of information. if it is less than the %maxlines% variable it simply adds the line to the current file.

The :countLines subroutine below accepts two parameters: a variable name; and a filename. The number of lines in the file are counted, the result is stored in the variable, and the result is passed back to the main program.

The code has the following features:

• Reads files with Windows or Unix line endings.
• Handles Unicode as well as ANSI/ASCII text files.
• Copes with extremely long lines.
• Isn’t fazed by the null character.
• Raises an error on reading an empty file.
• Counts beyond the Batch max int limit of (31^2)-1.

@echo off & setLocal enableExtensions disableDelayedExpansion

call :countLines noOfLines "%~1" || (
    >&2 echo(file "%~nx1" is empty & goto end
) %= cond exec =%
echo(file "%~nx1" has %noOfLines% line(s)

:end - exit program with appropriate errorLevel
endLocal & goto :EOF

:countLines result= "%file%"
:: counts the number of lines in a file
setLocal disableDelayedExpansion
(set "lc=0" & call)

for /f "delims=:" %%N in ('
    cmd /d /a /c type "%~2" ^^^& ^<nul set /p "=#" ^| (^
    2^>nul findStr /n "^" ^&^& echo(^) ^| ^
    findStr /blv 1: ^| 2^>nul findStr /lnxc:" "
') do (set "lc=%%N" & call;) %= for /f =%

endlocal & set "%1=%lc%"
exit /b %errorLevel% %= countLines =%

I know it looks hideous, but it covers most edge-cases and is surprisingly fast.

You can pipe the output of type into find inside the in(…) clause of a for /f loop:

for /f %%A in ('
    type "%~dpf1" ^| find /c /v ""
') do set "lineCount=%%A"

But the pipe starts a subshell, which slows things down.

Or, you could redirect input from the file into find like so:

for /f %%A in ('
    find /c /v "" ^< "%~dpf1"
') do set "lineCount=%%A"

But this approach will give you an answer 1 less than the actual number of lines if the file ends with one or more blank lines, as teased out by the late foxidrive in counting lines in a file.

And then again, you could always try:

find /c /v "" example.txt

The trouble is, the output from the above command looks like this:

---------- EXAMPLE.TXT: 511

You could split the string on the colon to get the count, but there might be more than one colon if the filename had a full path.

Here’s my take on that problem:

for /f "delims=" %%A in ('
    find /c /v "" "%~1"
') do for %%B in (%%A) do set "lineCount=%%B"

This will always store the count in the variable.

Just one last little problem… find treats null characters as newlines. So if sneaky nulls crept into your text file, or if you want to count the lines in a Unicode file, this answer isn’t for you.

In the below code, the variable name are SalaryCount and TaxCount

@ECHO OFF    
echo Process started, please wait...    
for /f %%C in ('Find /V /C "" ^< "D:\Trial\Salary.txt"') do set SalaryCount=%%C    
echo Salary,%SalaryCount%
for /f %%C in ('Find /V /C "" ^< "D:\Trial\Tax.txt"') do set TaxCount=%%C
echo Tax,%TaxCount%

Now if you need to output these values to a csv file, you could use the below code.

@ECHO OFF
cd "D:\CSVOutputPath\"
echo Process started, please wait...
echo FILENAME,FILECOUNT> SUMMARY.csv
for /f %%C in ('Find /V /C "" ^< "D:\Trial\Salary.txt"') do set Count=%%C
echo Salary,%Count%>> SUMMARY.csv
for /f %%C in ('Find /V /C "" ^< "D:\Trial\Tax.txt"') do set Count=%%C
echo Tax,%Count%>> SUMMARY.csv

The > will overwrite the existing content of the file and the >> will append the new data to existing data. The CSV will be generated in D:\CSVOutputPath

for /f "usebackq" %A in (`TYPE c:\temp\file.txt ^| find /v /c "" `) do set numlines=%A

in a batch file, use %%A instead of %A

I usually use something more like this for /f %%a in (%_file%) do (set /a Lines+=1)

Just:

c:\>(for /r %f in (*.java) do @type %f ) | find /c /v ""

Font: https://superuser.com/questions/959036/what-is-the-windows-equivalent-of-wc-l

Inspired by the previous posts, a shorter way of doing so:

CMD.exe
C:\>FINDSTR /R /N "^.*$" file.txt | FIND /C ":"

The number of lines

Try it. It works in my console.

EDITED:

(the "$" sign removed)

FINDSTR /R /N "^.*" file.txt | FIND /C ":"

$ reduces the number by 1 because it is accepting the first row as Field name and then counting the number of rows.

Try this:

@Echo off
Set _File=file.txt
Set /a _Lines=0
For /f %%j in ('Find "" /v /c ^< %_File%') Do Set /a _Lines=%%j
Echo %_File% has %_Lines% lines.

It eliminates the extra FindStr and doesn't need expansion.

- edited to use ChrisJJ's redirect suggestion. Removal of the TYPE command makes it three times faster.