I wrote this code to disable submit buttons on my website after the click:
$('input[type=submit]').click(function(){
$(this).attr('disabled', 'disabled');
});
Unfortunately, it doesn't send the form. How can I fix this?
EDIT I'd like to bind the submit, not the form :)
This question is related to
javascript
jquery
The following worked for me:
var form_enabled = true;
$().ready(function(){
// allow the user to submit the form only once each time the page loads
$('#form_id').on('submit', function(){
if (form_enabled) {
form_enabled = false;
return true;
}
return false;
});
});
This cancels the submit event if the user tries to submit the form multiple times (by clicking a submit button, pressing Enter, etc.)
How to disable submit button
just call a function on onclick event and... return true to submit and false to disable submit. OR call a function on window.onload like :
window.onload = init();
and in init() do something like this :
var theForm = document.getElementById(‘theForm’);
theForm.onsubmit = // what ever you want to do
This should take care of it in your app.
$(":submit").closest("form").submit(function(){
$(':submit').attr('disabled', 'disabled');
});
Simple and effective solution is
<form ... onsubmit="myButton.disabled = true; return true;">
...
<input type="submit" name="myButton" value="Submit">
</form>
Source: here
If you are using button of type submit and want to submit value of button as well, which will not happen if the button is disabled, you can set a form data attribute and test afterwards.
// Add class disableonsubmit to your form
$(document).ready(function () {
$('form.disableonsubmit').submit(function(e) {
if ($(this).data('submitted') === true) {
// Form is already submitted
console.log('Form is already submitted, waiting response.');
// Stop form from submitting again
e.preventDefault();
} else {
// Set the data-submitted attribute to true for record
$(this).data('submitted', true);
}
});
});
A more simplier way. I've tried this and it worked fine for me:
$(':input[type=submit]').prop('disabled', true);
Button Code
<button id="submit" name="submit" type="submit" value="Submit">Submit</button>
Disable Button
if(When You Disable the button this Case){
$(':input[type="submit"]').prop('disabled', true);
}else{
$(':input[type="submit"]').prop('disabled', false);
}
Note: You Case may Be Multiple this time more condition may need
Your code actually works on FF, it doesn't work on Chrome.
This works on FF and Chrome.
$(document).ready(function() {
// Solution for disabling the submit temporarily for all the submit buttons.
// Avoids double form submit.
// Doing it directly on the submit click made the form not to submit in Chrome.
// This works in FF and Chrome.
$('form').on('submit', function(e){
//console.log('submit2', e, $(this).find('[clicked=true]'));
var submit = $(this).find('[clicked=true]')[0];
if (!submit.hasAttribute('disabled'))
{
submit.setAttribute('disabled', true);
setTimeout(function(){
submit.removeAttribute('disabled');
}, 1000);
}
submit.removeAttribute('clicked');
e.preventDefault();
});
$('[type=submit]').on('click touchstart', function(){
this.setAttribute('clicked', true);
});
});
</script>
Specifically if someone is facing problem in Chrome
:
What you need to do to fix this is to use the onSubmit
tag in the <form>
element to set the submit button disabled
. This will allow Chrome to disable the button immediately after it is pressed and the form submission will still go ahead...
<form name ="myform" method="POST" action="dosomething.php" onSubmit="document.getElementById('submit').disabled=true;">
<input type="submit" name="submit" value="Submit" id="submit">
</form>
I have been using blockUI to avoid browser incompatibilies on disabled or hidden buttons.
http://malsup.com/jquery/block/#element
Then my buttons have a class autobutton:
$(".autobutton").click(
function(event) {
var nv = $(this).html();
var nv2 = '<span class="fa fa-circle-o-notch fa-spin" aria-hidden="true"></span> ' + nv;
$(this).html(nv2);
var form = $(this).parents('form:first');
$(this).block({ message: null });
form.submit();
});
Then a form is like that:
<form>
....
<button class="autobutton">Submit</button>
</form>
Disabled controls do not submit their values which does not help in knowing if the user clicked save or delete.
So I store the button value in a hidden which does get submitted. The name of the hidden is the same as the button name. I call all my buttons by the name of button
.
E.g. <button type="submit" name="button" value="save">Save</button>
Based on this I found here. Just store the clicked button in a variable.
$(document).ready(function(){
var submitButton$;
$(document).on('click', ":submit", function (e)
{
// you may choose to remove disabled from all buttons first here.
submitButton$ = $(this);
});
$(document).on('submit', "form", function(e)
{
var form$ = $(this);
var hiddenButton$ = $('#button', form$);
if (IsNull(hiddenButton$))
{
// add the hidden to the form as needed
hiddenButton$ = $('<input>')
.attr({ type: 'hidden', id: 'button', name: 'button' })
.appendTo(form$);
}
hiddenButton$.attr('value', submitButton$.attr('value'));
submitButton$.attr("disabled", "disabled");
}
});
Here is my IsNull
function. Use or substitue your own version for IsNull or undefined etc.
function IsNull(obj)
{
var is;
if (obj instanceof jQuery)
is = obj.length <= 0;
else
is = obj === null || typeof obj === 'undefined' || obj == "";
return is;
}
Source: Stackoverflow.com