How can I print each command before executing

Question

What is the best way to set up a Bash script that prints each command before it executes it   That would be great for debugging purposes   I already tried this   CMD    my-command --params  gt stdout txt 2 gt stderr txt  echo  CMD   CMD    It s supposed to print this first     my-command --params  gt stdout txt 2 gt stderr txt   And then execute   my-command --params  with the output redirected to the files specified

User · Answer

set -x is fine  but if you do something like   set -x  command  set  x    it would result in printing    command   set  x    You can use a subshell to prevent that such as    set -x  command    which would just print the command

User · Answer

The easiest way to do this is to let bash do it   set -x   Or run it explicitly as bash -x myscript

User · Answer

set -o xtrace   or  bash -x myscript sh   This works with standard  bin sh as well IIRC  it might be a POSIX thing then   And remember  there is bashdb  bash Shell Debugger  release 4 0-0 4     To revert to normal  exit the subshell or  set  o xtrace

User · Answer

set -x is fine   Another way to print each executed command is to use trap with DEBUG  Put this line at the beginning of your script    trap  echo     BASH COMMAND   DEBUG   You can find a lot of other trap usages here

[bash] How can I print each command before executing?

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