[python] How to put multiple statements in one line?

I wasn't sure under what title to ponder this question exactly, coding golf seems appropriate if a bit unspecific.

I know a little bit of comprehensions in python but they seem very hard to 'read'. The way I see it, a comprehension might accomplish the same as the following code:

for i in range(10): if i == 9: print('i equals 9')

This code is much easier to read than how comprehensions currently work but I've noticed you cant have two : in one line ... this brings me too...

my question:

Is there any way I can get the following example into ONE LINE?

try:
    if sam[0] != 'harry':
        print('hello',  sam)
except:
    pass

Something like this would be great:

try: if sam[0] != 'harry': print('hellp',  sam)
except:pass

But again I encounter the conflicting : I'd also love to know if there's a way to run try (or something like it) without except, it seems entirely pointless that I need to put except:pass in there. its a wasted line.

maybe with "and" or "or"

after false need to write "or"

after true need to write "and"

like

n=0
def returnsfalse():
    global n
    n=n+1
    print ("false %d" % (n))
    return False
def returnstrue():
    global n
    n=n+1
    print ("true %d" % (n))
    return True
n=0
returnsfalse() or  returnsfalse() or returnsfalse() or returnstrue() and returnsfalse()

result:

false 1
false 2
false 3
true 4
false 5

or maybe like

(returnsfalse() or true) and (returnstrue() or true) and ...

got here by searching google "how to put multiple statments in one line python", not answers question directly, maybe somebody else needs this.

Yes this post is 8 years old, but incase someone comes on here also looking for an answer: you can now just use semicolons. However, you cannot use if/elif/else staments, for/while loops, and you can't define functions. The main use of this would be when using imported modules where you don't have to define any functions or use any if/elif/else/for/while statements/loops.

Here's an example that takes the artist of a song, the song name, and searches genius for the lyrics:

import bs4, requests; song = input('Input artist then song name\n'); print(bs4.BeautifulSoup(requests.get(f'https://genius.com/{song.replace(" ", "-")}-lyrics').text,'html.parser').select('.lyrics')[0].text.strip())

You are mixing a lot of things, which makes it hard to answer your question. The short answer is: As far as I know, what you want to do is just not possible in Python - for good reason!

The longer answer is that you should make yourself more comfortable with Python, if you want to develop in Python. Comprehensions are not hard to read. You might not be used to reading them, but you have to get used to it if you want to be a Python developer. If there is a language that fits your needs better, choose that one. If you choose Python, be prepared to solve problems in a pythonic way. Of course you are free to fight against Python, But it will not be fun! ;-)

And if you would tell us what your real problem is, you might even get a pythonic answer. "Getting something in one line" us usually not a programming problem.

Here is an example:

for i in range(80, 90): print(i, end=" ") if (i!=89) else print(i)

Output:

80 81 82 83 84 85 86 87 88 89
>>>

I recommend not doing this...

What you are describing is not a comprehension.

PEP 8 Style Guide for Python Code, which I do recommend, has this to say on compound statements:

• Compound statements (multiple statements on the same line) are generally discouraged.

Yes:

      if foo == 'blah':
          do_blah_thing()
      do_one()
      do_two()
      do_three()

Rather not:

      if foo == 'blah': do_blah_thing()
      do_one(); do_two(); do_three()

Here is a sample comprehension to make the distinction:

>>> [i for i in xrange(10) if i == 9]
[9]

You could use the built-in exec statement, eg.:

exec("try: \n \t if sam[0] != 'harry': \n \t\t print('hello',  sam) \nexcept: pass")

Where \n is a newline and \t is used as indentation (a tab).
Also, you should count the spaces you use, so your indentation matches exactly.

However, as all the other answers already said, this is of course only to be used when you really have to put it on one line.

exec is quite a dangerous statement (especially when building a webapp) since it allows execution of arbitrary Python code.

Its acctualy possible ;-)

# not pep8 compatible^
sam = ['Sam',]
try: print('hello',sam) if sam[0] != 'harry' else rais
except: pass

You can do very ugly stuff in python like:

def o(s):return''.join([chr(ord(n)+(13if'Z'<n<'n'or'N'>n else-13))if n.isalpha()else n for n in s])

which is function for rot13/cesa encryption in one line with 99 characters.

I know I am late, but stumped into the question, and based on ThomasH's answer:

for i in range(4): print "i equals 3" if i==3 else None

output: None None None i equals 3

I propose to update as:

for i in range(4): print("i equals 3") if i==3 else print('', end='')

output: i equals 3

Note, I am in python3 and had to use two print commands. pass after else won't work. Wanted to just comment on ThomasH's answer, but can't because I don't have enough reputation yet.

I do not incentivise this, but say you're on command line, you have nothing but Python and you really need a one-liner, you can do this:

python -c "$(echo -e "a='True'\nif a : print 1")"

What we're doing here is pre-processing \n before evaluating Python code.

That's super hacky! Don't write code like this.

For a python -c oriented solution, and provided you use Bash shell, yes you can have a simple one-line syntax like in this example:

Suppose you would like to do something like this (very similar to your sample, including except: pass instruction):

python -c  "from __future__ import print_function\ntry: import numpy; print( numpy.get_include(), end='\n' )\nexcept:pass\n" OUTPUT_VARIABLE __numpy_path

This will NOT work and produce this Error:

  File "<string>", line 1
    from __future__ import print_function\ntry: import numpy; print( numpy.get_include(), end='\n' )\nexcept:pass\n
                                                                                                                  ^
SyntaxError: unexpected character after line continuation character `

This is because the competition between Bash and Python Interpretation of \n escape sequences. To solve the problem one can use the $'string' Bash syntax to force \n Bash interpretation BEFORE the Python one. To make the example more challenging I added a typical Python end=..\n.. specification in the Python print call: at the end you will be able to get BOTH \n interpretations from bash and Python working together, each on its piece of text of concern. So that finally the proper solution is like this :

python -c  $'from __future__ import print_function\ntry:\n import numpy;\n print( numpy.get_include(), end="\\n" )\n print( "Hello" )\nexcept:pass\n' OUTPUT_VARIABLE __numpy_path

That leads to the proper clean output with no error:

/Softs/anaconda/lib/python3.7/site-packages/numpy/core/include
Hello

Note: this should work as well with exec oriented solutions, because the problem is still the same (Bash and Python interpreters competition).

Note2: one could workaround the problem by replacing some \n by some ; but it will not work anytime (depending on Python constructs), while my solution allows to always "one-line" any piece of classic multi-line Python program.

Note3: of course, when one-lining, one has always to take care of Python spaces and indentation, because in fact we are not strictly "one-lining" here, BUT doing a proper mixed-management of \n escape sequence between bash and Python. This is how we can deal with any piece of classic multi-line Python program. The solution sample illustrates this as well.

if you want it without try and except then there is the solution

what you are trying to do is print 'hello' if 'harry' in a list then the solution is

'hello' if 'harry' in sam else ''