[python] Printing list elements on separated lines in Python

I am trying to print out Python path folders using this:

import sys
print sys.path

The output is like this:

>>> print sys.path
['.', '/usr/bin', '/home/student/Desktop', '/home/student/my_modules', '/usr/lib/pyth
on2.6', '/usr/lib/python2.6/plat-linux2', '/usr/lib/python2.6/lib-tk', '/usr/lib/pyth
on2.6/lib-old', '/usr/lib/python2.6/lib-dynload', '/usr/local/lib/python2.6/dist-pack
ages', '/usr/lib/python2.6/dist-packages', '/usr/lib/python2.6/dist-packages/PIL', '/
usr/lib/python2.6/dist-packages/gst-0.10', '/usr/lib/pymodules/python2.6', '/usr/lib/
python2.6/dist-packages/gtk-2.0', '/usr/lib/pymodules/python2.6/gtk-2.0', '/usr/lib/p
ython2.6/dist-packages/wx-2.8-gtk2-unicode']

How do I print them into separate lines so I can parse them properly?

It should be like this:

/usr/bin
/home/student/Desktop
/home/student/my_modules
etc

Sven Marnach's answer is pretty much it, but has one generality issue... It will fail if the list being printed doesn't just contain strings.

So, the more general answer to "How to print out a list with elements separated by newlines"...

print '\n'.join([ str(myelement) for myelement in mylist ])

Then again, the print function approach JBernardo points out is superior. If you can, using the print function instead of the print statement is almost always a good idea.

A slightly more general solution based on join, that works even for pandas.Timestamp:

print("\n".join(map(str, my_list)))

print("\n".join(sys.path))

(The outer parentheses are included for Python 3 compatibility and are usually omitted in Python 2.)

for path in sys.path:
    print path

Use the splat operator(*)

By default, * operator prints list separated by space. Use sep operator to specify the delimiter

print(*sys.path, sep = "\n")

Use the print function (Python 3.x) or import it (Python 2.6+):

from __future__ import print_function

print(*sys.path, sep='\n')

Another good option for handling this kind of option is the pprint module, which (among other things) pretty prints long lists with one element per line:

>>> import sys
>>> import pprint
>>> pprint.pprint(sys.path)
['',
 '/usr/lib/python27.zip',
 '/usr/lib/python2.7',
 '/usr/lib/python2.7/plat-linux2',
 '/usr/lib/python2.7/lib-tk',
 '/usr/lib/python2.7/lib-old',
 '/usr/lib/python2.7/lib-dynload',
 '/usr/lib/python2.7/site-packages',
 '/usr/lib/python2.7/site-packages/PIL',
 '/usr/lib/python2.7/site-packages/gst-0.10',
 '/usr/lib/python2.7/site-packages/gtk-2.0',
 '/usr/lib/python2.7/site-packages/setuptools-0.6c11-py2.7.egg-info',
 '/usr/lib/python2.7/site-packages/webkit-1.0']
>>> 

sys.path returns the list of paths

ref

sys.path

A list of strings that specifies the search path for modules. Initialized from the environment variable PYTHONPATH, plus an installation-dependent default.

As initialized upon program startup, the first item of this list, path[0], is the directory containing the script that was used to invoke the Python interpreter. If the script directory is not available (e.g. if the interpreter is invoked interactively or if the script is read from standard input), path[0] is the empty string, which directs Python to search modules in the current directory first. Notice that the script directory is inserted before the entries inserted as a result of PYTHONPATH.

import sys
dirs=sys.path
for path in dirs:
   print(path)

or you can print only first path by

print(dir[0])