$.each() works for objects and arrays both:
var data = { "programs": [ { "name":"zonealarm", "price":"500" }, { "name":"kaspersky", "price":"200" } ] };
$.each(data.programs, function (i) {
$.each(data.programs[i], function (key, val) {
alert(key + val);
});
});
...and since you will get the current array element as second argument:
$.each(data.programs, function (i, currProgram) {
$.each(currProgram, function (key, val) {
alert(key + val);
});
});