Count all duplicates of each value

Question

I would like a SQL query for MS Jet 4 0  MSSql   to get a count of all the duplicates of each number in a database   The fields are  id  autonum   number  text     I have a database with a lot of numbers   Each number should be returned in numerical order  without duplicates  with a count of all duplicates   Number-fields containing 1  2  2  3  1  4  2 should return   1  2   2  3   3  1   4  1

User · Answer

This is quite simple   Assuming the data is stored in a column called A in a table called T  you can use  select A  count A  from T group by A

User · Answer

You d want the COUNT operator   SELECT NUMBER  COUNT     FROM T NAME GROUP BY NUMBER ORDER BY NUMBER ASC

User · Answer

SELECT   col           COUNT dupe col  AS dupe cnt FROM     TABLE GROUP BY col HAVING   COUNT dupe col   gt  1 ORDER BY COUNT dupe col  DESC

User · Answer

If you want to check repetition more than 1 in descending order  then implement below query   SELECT   duplicate data COUNT duplicate data  AS duplicate data FROM     duplicate data table name  GROUP BY duplicate data HAVING   COUNT duplicate data   gt  1 ORDER BY COUNT duplicate data  DESC   If want simple count query   SELECT   COUNT duplicate data  AS duplicate data FROM     duplicate data table name  GROUP BY duplicate data ORDER BY COUNT duplicate data  DESC

User · Answer

SELECT number  COUNT        FROM YourTable     GROUP BY number     ORDER BY number

[sql] Count all duplicates of each value

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