Count all duplicates of each value

Question

I would like a SQL query for MS Jet 4 0  MSSql   to get a count of all the duplicates of each number in a database   The fields are  id  autonum   number  text     I have a database with a lot of numbers   Each number should be returned in numerical order  without duplicates  with a count of all duplicates   Number-fields containing 1  2  2  3  1  4  2 should return   1  2   2  3   3  1   4  1

User · Answer

If you want to check repetition more than 1 in descending order then implement below query.

SELECT   duplicate_data,COUNT(duplicate_data) AS duplicate_data
FROM     duplicate_data_table_name 
GROUP BY duplicate_data
HAVING   COUNT(duplicate_data) > 1
ORDER BY COUNT(duplicate_data) DESC

If want simple count query.

SELECT   COUNT(duplicate_data) AS duplicate_data
FROM     duplicate_data_table_name 
GROUP BY duplicate_data
ORDER BY COUNT(duplicate_data) DESC

User · Answer

This is quite simple   Assuming the data is stored in a column called A in a table called T  you can use  select A  count A  from T group by A

User · Answer

SELECT number  COUNT        FROM YourTable     GROUP BY number     ORDER BY number

User · Answer

SELECT   col           COUNT dupe col  AS dupe cnt FROM     TABLE GROUP BY col HAVING   COUNT dupe col   gt  1 ORDER BY COUNT dupe col  DESC

User · Answer

You d want the COUNT operator   SELECT NUMBER  COUNT     FROM T NAME GROUP BY NUMBER ORDER BY NUMBER ASC

[sql] Count all duplicates of each value

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