Reading string from input with space character

Question

I m using Ubuntu and I m also using Geany and CodeBlock as my IDE  What I m trying to do is reading a string  like  Barack Obama   and put it in a variable    include  lt stdio h gt   int main void        char name 100        printf  Enter your name          scanf   s   name       printf  Your Name is   s   name        return 0      Output   Enter your name  Barack Obama Your Name is  Barack   How can I make the program read the whole name

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If you need to read more than one line  need to clear buffer  Example   int n  scanf   d    amp n   char str 1001   char temp  scanf   c   amp temp      temp statement to clear buffer scanf      n   str

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include lt stdio h gt  int main        char name 100      printf  Enter your name         scanf      n s  name      printf  Your Name is   s  name      return 0

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While the above mentioned methods do work  but each one has it s own kind of problems   You can use getline   or getdelim    if you are using posix supported platform  If you are using windows and minigw as your compiler  then it should be available   getline   is defined as    ssize t getline char   lineptr  size t  n  FILE  stream    In order to take input  first you need to create a pointer to char type    include  lt stdio h gt   include lt stdlib h gt      s is a pointer to char type  char  s     size is of size t type  this number varies based on your guess of     how long the input is  even if the number is small  it isn t going     to be a problem size t size   10   int main       allocate s with the necessary memory needed   1 is added     as its input also contains   n character at the end      s    char   malloc size 1       getline  amp s  amp size stdin       printf   s  s       return 0      Sample Input Hello world to the world   Output Hello world to the world  n  One thing to notice here is  even though allocated memory for s is 11 bytes  where as input size is 26 bytes  getline reallocates s using realloc     So it doesn t matter how long your input is   size is updated with no of bytes read  as per above sample input size will be 27   getline   also considers  n as input So your  s  will hold   n  at the end   There is also more generic version of getline    which is getdelim    which takes one more extra argument  that is delimiter   getdelim   is defined as   ssize t getdelim char   lineptr  size t  n  int delim  FILE  stream    Linux man page

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include  lt stdio h gt     read a line into str  return length int read line char str      int c  i 0  c   getchar    while  c      n   amp  amp  c    EOF        str i    c     c   getchar       i      str i      0   return i

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Barack Obama  has a space between  Barack  and  Obama   To accommodate that  use this code    include  lt stdio h gt  int main         printf  Enter your name n       char a 80      gets a      printf  Your name is  s n   a      return 0

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Try this   scanf      n s  name      n just sets the delimiter for the scanned string

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s  will read the input until whitespace is reached   gets might be a good place to start if you want to read a line  i e  all characters including whitespace until a newline character is reached

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scanf       t n s   amp str     str is the variable in which you are getting the string from

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Use   fgets  name  100  stdin     100 is the max length of the buffer  You should adjust it as per your need   Use   scanf       n   c   name     The    is the scanset character     n  tells that while the input is not a newline    n   take input  Then with the   c it reads the newline character from the input buffer  which is not read   and the   indicates that this read in input is discarded  assignment suppression   as you do not need it  and this newline in the buffer does not create any problem for next inputs that you might take   Read here about the scanset and the assignment suppression operators   Note you can also use gets but          Never use gets     Because it is impossible to tell without knowing the data  in  advance  how  many  characters  gets   will read  and because gets   will continue to store characters past the end of the buffer  it is  extremely  dangerous  to  use    It has been used to break computer security  Use fgets   instead

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Using this code you can take input till pressing enter of your keyboard      char ch 100   int i  for  i   0  ch i       n   i          scanf   c     amp ch i

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Here is an example of how you can get input containing spaces by using the fgets function     include  lt stdio h gt   int main         char name 100       printf  Enter your name          fgets name  100  stdin        printf  Your Name is   s   name       return 0

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NOTE  When using fgets    the last character in the array will be   n  at times when you use fgets   for small inputs in CLI  command line interpreter    as you end the string with  Enter   So when you print the string the compiler will always go to the next line when printing the string  If you want the input string to have null terminated string like behavior  use this simple hack    include lt stdio h gt  int main      int i size   char a 100    fgets a 100 stdin     size   strlen a    a size-1    0    return 0      Update  Updated with help from other users

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The correct answer is this    include  lt stdio h gt   int main void        char name 100        printf  Enter your name             pay attention to the space in front of the         that do all the trick     scanf       n s   name       printf  Your Name is   s   name        return 0      That space in front of   is very important  because if you have in your program another few scanf let s say you have 1 scanf of an integer value and another scanf with a double value    when you reach the scanf for your char  string name  that command will be skipped and you can t enter value for it    but if you put that space in front of   will be ok everything and not skip nothing

User · Answer

scanf   s  name     use  amp  with scanf input

[c] Reading string from input with space character?

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