[javascript] Replace all whitespace characters

I want to replace all occurrences of white space characters (space, tab, newline) in JavaScript.
How to do so?

I tried:

str.replace(/ /gi, "X")

This question is related to javascript trim

The answer is


You could use the function trim

let str = ' Hello World ';

alert (str.trim());

All the front and back spaces around Hello World would be removed.


Not /gi but /g

var fname = "My Family File.jpg"
fname = fname.replace(/ /g,"_");
console.log(fname);

gives

"My_Family_File.jpg"

We can also use this if we want to change all multiple joined blank spaces with a single character:

str.replace(/\s+/g,'X');

See it in action here: https://regex101.com/r/d9d53G/1

Explanation

/ \s+ / g

  • \s+ matches any whitespace character (equal to [\r\n\t\f\v ])
  • + Quantifier — Matches between one and unlimited times, as many times as possible, giving back as needed (greedy)

  • Global pattern flags
    • g modifier: global. All matches (don't return after first match)

Have you tried the \s?

str.replace(/\s/g, "X");

\s is a meta character that covers all white space. You don't need to make it case-insensitive — white space doesn't have case.

str.replace(/\s/g, "X")

Try this:

str.replace(/\s/g, "X")

Actually it has been worked but

just try this.

take the value /\s/g into a string variable like

String a = /\s/g;

str = str.replaceAll(a,"X");

If you use

str.replace(/\s/g, "");

it replaces all whitespaces. For example:

var str = "hello my world";
str.replace(/\s/g, "") //the result will be "hellomyworld"

I've used the "slugify" method from underscore.string and it worked like a charm:

https://github.com/epeli/underscore.string#slugifystring--string

The cool thing is that you can really just import this method, don't need to import the entire library.