Trim specific character from a string

Question

What s the JavaScript equivalent to this C  Method   var x     f oo      var y   x Trim            f oo    C  trims the selected character only at the beginning and end of the string

User · Answer

If you define these functions in your program, your strings will have an upgraded version of trim that can trim all given characters:

_x000D_

String.prototype.trimLeft = function(charlist) {_x000D_
 if (charlist === undefined)_x000D_
 charlist = "\s";_x000D_
_x000D_
 return this.replace(new RegExp("^[" + charlist + "]+"), "");_x000D_
};_x000D_
_x000D_
String.prototype.trim = function(charlist) {_x000D_
 return this.trimLeft(charlist).trimRight(charlist);_x000D_
};_x000D_
_x000D_
String.prototype.trimRight = function(charlist) {_x000D_
 if (charlist === undefined)_x000D_
 charlist = "\s";_x000D_
_x000D_
 return this.replace(new RegExp("[" + charlist + "]+$"), "");_x000D_
};_x000D_
_x000D_
var withChars = "/-center-/"_x000D_
var withoutChars = withChars.trim("/-")_x000D_
document.write(withoutChars)

_x000D_

Source

https://www.sitepoint.com/trimming-strings-in-javascript/

User · Answer

To my knowledge  jQuery doesnt have a built in function the method your are asking about  With javascript however  you can just use replace to change the content of your string   x replace    i          This will replace all occurences of   with nothing

User · Answer

expanding on  leaf  s answer  here s one that can take multiple characters    var trim   function  s  t      var tr  sr   tr   t split     map e   gt         e    join       sr   s replace new RegExp      tr       tr        g          return sr

User · Answer

function trim text  val        return text replace new RegExp     val      val       g

User · Answer

One line is enough   x000D   x000D  var x     f oo     var y   x replace            g       document write x     lt br   gt     y   x000D   x000D   x000D          beginning of the string  pipe  one or more times        or        pipe  one or more times  end of the string  A general solution   x000D   x000D  function trim  s  c      if  c          c            if  c           c             return s replace new RegExp             c            c           g               chars            for  c of chars      s   c    foo    c   c    oo    c   c   c    console log s   - gt    trim s  c      x000D   x000D   x000D

User · Answer

If I understood well  you want to remove a specific character only if it is at the beginning or at the end of the string  ex    fo  oo     should become foo  oo   You can create an ad hoc function as follows   function trimChar string  charToRemove        while string charAt 0   charToRemove            string   string substring 1              while string charAt string length-1   charToRemove            string   string substring 0 string length-1              return string      I tested this function with the code below   var str     f oo          original    html   Original String       str               trimmed    html   Trimmed       trimChar str

User · Answer

Try this method    x000D   x000D  var a    anan g  zel mi    x000D  if  a endsWith         a   a slice 0  -1     x000D  document body innerHTML   a  x000D   x000D   x000D

User · Answer

I would suggest looking at lodash and how they implemented the trim function   See Lodash Trim for the documentation and the source to see the exact code that does the trimming   I know this does not provide an exact answer your question  but I think it s good to set a reference to a library on such a question since others might find it useful

User · Answer

try   console log x replace     g

User · Answer

A regex-less version which is easy on the eye   const trim    str  chars    gt  str split chars  filter Boolean  join chars     For use cases where we re certain that there s no repetition of the chars off the edges

User · Answer

You can use a regular expression such as  var x    quot  f oo   quot   var y   x replace            g   quot  quot    alert y      f oo  UPDATE  Should you wish to generalize this into a function  you can do the following  var escapeRegExp   function strToEscape           Escape special characters for use in a regular expression     return strToEscape replace    -                                g   quot     amp  quot        var trimChar   function origString  charToTrim        charToTrim   escapeRegExp charToTrim       var regEx   new RegExp  quot    quot    charToTrim    quot      quot    charToTrim    quot     quot    quot g quot        return origString replace regEx   quot  quot        var x    quot  f oo   quot   var y   trimChar x   quot   quot    alert y      f oo

User · Answer

to keep this question up to date  here is an approach i d choose over the regex function using the ES6 spread operator  function trimByChar string  character      const first       string  findIndex char   gt  char     character     const last       string  reverse   findIndex char   gt  char     character     return string substring first  string length - last      Improved version after  fabian  s comment  can handle strings containing the same character only   x000D   x000D  function trimByChar1 string  character      const arr   Array from string     const first   arr findIndex char   gt  char     character     const last   arr reverse   findIndex char   gt  char     character     return  first     -1  amp  amp  last     -1         string substring first  string length - last     x000D   x000D   x000D

User · Answer

If you re dealing with longer strings I believe this should outperform most of the other options by reducing the number of allocated strings to either zero or one   function trim str  ch        var start   0           end   str length       while start  lt  end  amp  amp  str start      ch            start       while end  gt  start  amp  amp  str end - 1      ch          --end       return  start  gt  0    end  lt  str length    str substring start  end    str        Usage  trim   hello world               gt   hello world    Or if you want to trim from a set of multiple characters   function trimAny str  chars        var start   0           end   str length       while start  lt  end  amp  amp  chars indexOf str start    gt   0            start       while end  gt  start  amp  amp  chars indexOf str end - 1    gt   0          --end       return  start  gt  0    end  lt  str length    str substring start  end    str        Usage  trimAny   hello world                          gt   hello world     because   indexOf  is used  you could also pass a string for the 2nd parameter  trimAny   hello  world                 gt   hello world    EDIT  For fun  trim words  rather than individual characters      Helper function to detect if a string contains another string        at a specific position      Equivalent to using  str indexOf substr  pos      pos  but  should  be more efficient on longer strings as it can exit early  needs benchmarks to back this up   function hasSubstringAt str  substr  pos        var idx   0  len   substr length       for  var max   str length  idx  lt  len    idx            if   pos   idx   gt   max    str pos   idx     substr idx               break             return idx     len     function trimWord str  word        var start   0          end   str length          len   word length       while  start  lt  end  amp  amp  hasSubstringAt str  word  start           start    word length       while  end  gt  start  amp  amp  hasSubstringAt str  word  end - len           end -  word length      return  start  gt  0    end  lt  str length    str substring start  end    str        Usage  trimWord  blahrealmessageblah    blah

User · Answer

This one trims all leading and trailing delimeters  const trim    str  delimiter    gt      const pattern          delimiter       const start   str search pattern     const stop   str length - str split     reverse   join     search pattern     return str substring start  stop      const test      2 aaaa12bb3ccc        console log trim test            2 aaaa12bb3ccc

User · Answer

This can trim several characters at a time  function trimChars  str  c      var re   new RegExp  quot    quot    c    quot      quot    c    quot     quot    quot g quot      return str replace re  quot  quot       var x    quot  f oo   quot    x    trimChars x           f oo  var y    quot      f oo       quot   y   trimChars y             f oo  var z    quot   f oo   quot       f oo      For backslash  remember to double-escape  z   trimChars z   quot      quot       f oo  For use in your own script and if you don t mind changing the prototype  this can be a convenient  quot hack quot   String prototype trimChars   function  c      var re   new RegExp  quot    quot    c    quot      quot    c    quot     quot    quot g quot      return this replace re  quot  quot       var x    quot  f oo   quot    x    x trimChars          f oo  Since I use the trimChars function extensively in one of my scripts  I prefer this solution  But there are potential issues with modifying an object s prototype

User · Answer

x000D   x000D  const special        lt  gt            amp      -    split      const trim    input    gt        const inTrim    str    gt            const spStr   str split              let deleteTill   0          let startChar   spStr deleteTill           while  special some  s    gt  s     startChar                 deleteTill                if  deleteTill  lt   spStr length                    startChar   spStr deleteTill                 else                   deleteTill--                  break                                  spStr splice 0  deleteTill           return spStr join             input   inTrim input   input   inTrim input split     reverse   join      split     reverse   join      return input     alert trim    This is what I use       x000D   x000D   x000D

User · Answer

I like the solution from  Pho3niX83     Let s extend it with  word  instead of  char      function trimWord  string   word         var splitted    string split  word        while  splitted length  amp  amp  splitted 0                    splitted shift              while  splitted length  amp  amp  splitted splitted length - 1                    splitted pop              return splitted join  word

User · Answer

Howdy  replace new RegExp                 note the double escaping     needed  to have an actually single slash in the string  that then leads to escaping of   in the regExp    Only few characters need regExp-Escaping   among them the pipe operator

User · Answer

String prototype TrimStart   function  n        if  this charAt 0     n          return this substr 1       String prototype TrimEnd   function  n        if  this slice -1     n          return this slice 0  -1

User · Answer

The best way to resolve this task is  similar with PHP trim function     x000D   x000D  function trim  str  charlist     x000D    if   typeof charlist     undefined      x000D      charlist      s   x000D      x000D     x000D    var pattern          charlist                charlist          x000D     x000D    return str replace  new RegExp  pattern       1    x000D    x000D   x000D  document getElementById   run    onclick   function     x000D    document getElementById   result    value    x000D    trim  document getElementById   input    value  x000D    document getElementById   charlist    value   x000D    x000D   lt div gt  x000D     lt label for  input  gt Text to trim  lt  label gt  lt br gt  x000D     lt input id  input  type  text  placeholder  Text to trim  value  dfstextfsd  gt  lt br gt  x000D     lt label for  charlist  gt Charlist  lt  label gt  lt br gt  x000D     lt input id  charlist  type  text  placeholder  Charlist  value  dfs  gt  lt br gt  x000D     lt label for  result  gt Result  lt  label gt  lt br gt  x000D     lt input id  result  type  text  placeholder  Result  disabled gt  lt br gt  x000D     lt button type  button  id  run  gt Trim it  lt  button gt  x000D   lt  div gt  x000D   x000D   x000D    P S   why i posted my answer  when most people already done it before  Because i found  the best  mistake in all of there answers  all used the     meta instead of       cause trim must remove chars IF THEY ARE IN START AND OR END  but it return original string in else case

[javascript] Trim specific character from a string

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