[java] Conversion from 12 hours time to 24 hours time in java

In my app, I have a requirement to format 12 hours time to 24 hours time. What is the method I have to use?

For example, time like 10:30 AM. How can I convert to 24 hours time in java?

This question is related to java time

The answer is


Try this:

import java.text.SimpleDateFormat;
import java.util.Date;

public class Main {
   public static void main(String [] args) throws Exception {
       SimpleDateFormat displayFormat = new SimpleDateFormat("HH:mm");
       SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm a");
       Date date = parseFormat.parse("10:30 PM");
       System.out.println(parseFormat.format(date) + " = " + displayFormat.format(date));
   }
}

which produces:

10:30 PM = 22:30

See: http://download.oracle.com/javase/1.5.0/docs/api/java/text/SimpleDateFormat.html


I was looking for same thing but in number, means from integer xx hour, xx minutes and AM/PM to 24 hour format xx hour and xx minutes, so here what i have done:

private static final int AM = 0;
private static final int PM = 1;
/**
   * Based on concept: day start from 00:00AM and ends at 11:59PM, 
   * afternoon 12 is 12PM, 12:xxAM is basically 00:xxAM
   * @param hour12Format
   * @param amPm
   * @return
   */
  private int get24FormatHour(int hour12Format,int amPm){
    if(hour12Format==12 && amPm==AM){
      hour12Format=0;
    }
    if(amPm == PM && hour12Format!=12){
      hour12Format+=12;
    }
    return hour12Format;
  }`

    private int minutesTillMidnight(int hour12Format,int minutes, int amPm){
        int hour24Format=get24FormatHour(hour12Format,amPm);
        System.out.println("24 Format :"+hour24Format+":"+minutes); 
        return (hour24Format*60)+minutes;
      }

import java.text.SimpleDateFormat;
import java.text.DateFormat;
import java.util.Date;

public class Main {
   public static void main(String [] args){
       try {
            DateFormat parseFormat = new SimpleDateFormat("dd-MM-yyyy hh:mm:ss a");
            String sDate = "22-01-2019 9:0:0 PM";
            Date date = parseFormat.parse(sDate);
            SimpleDateFormat displayFormat = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
            sDate = displayFormat.format(date);
            LOGGER.info("The required format : " + sDate);
           } catch (Exception e) {}
      }
}

This is the extract of code that I have done.

    String s="08:10:45";
    String[] s1=s.split(":");
    int milipmHrs=0;
    char[] arr=s1[2].toCharArray();
    boolean isFound=s1[2].contains("PM");
    if(isFound){
        int pmHrs=Integer.parseInt(s1[0]);
        milipmHrs=pmHrs+12;
        return(milipmHrs+":"+s1[1]+":"+arr[0]+arr[1]);
    }
    else{

        return(s1[0]+":"+s1[1]+":"+arr[0]+arr[1]);
    }

I have written a simple utility function.

public static String convert24HourTimeTo12Hour(String timeStr) {
    try {
        DateFormat inFormat = new SimpleDateFormat( "HH:mm:ss");
        DateFormat outFormat = new SimpleDateFormat( "hh:mm a");
        Date date = inFormat.parse(timeStr);
        return outFormat.format(date);
    }catch (Exception e){}

    return "";
}

Try this to calculate time difference between two times.

first it will convert 12 hours time into 24 hours then it will take diff between two times

String a = "09/06/18 01:55:33 AM";
            String b = "07/06/18 05:45:33 PM";
            String [] b2 = b.split(" ");
            String [] a2 = a.split(" ");
            SimpleDateFormat displayFormat = new SimpleDateFormat("HH:mm:ss");
            SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm:ss a");
            String time1 = null ;
            String time2 = null ;
            if ( a.contains("PM") && b.contains("AM")) {
                 
                 Date date = parseFormat.parse(a2[1]+" PM");
                 time1 = displayFormat.format(date);
                 time2 = b2[1];
            }else if (b.contains("PM") && a.contains("AM")) {
                Date date = parseFormat.parse(a2[1]+" PM");
                time1 = a2[1];
                time2 = displayFormat.format(date);
            }else if (a.contains("PM") && b.contains("PM")){
                Date datea = parseFormat.parse(a2[1]+" PM");
                Date dateb = parseFormat.parse(b2[1]+" PM");
                time1 = displayFormat.format(datea);
                time2 = displayFormat.format(dateb);
            }   
            System.out.println(time1);
            System.out.println(time2);      
            SimpleDateFormat format = new SimpleDateFormat("HH:mm:ss");
            Date date1 = format.parse(time1);
            Date date2 = format.parse(time2);
            long difference = date2.getTime() - date1.getTime(); 
            System.out.println(difference);
            System.out.println("Duration: "+DurationFormatUtils.formatDuration(difference, "HH:mm"));

For More Details Click Here


java.time

In Java 8 and later it could be done in one line using class java.time.LocalTime.

In the formatting pattern, lowercase hh means 12-hour clock while uppercase HH means 24-hour clock.

Code example:

String result =                                       // Text representing the value of our date-time object.
    LocalTime.parse(                                  // Class representing a time-of-day value without a date and without a time zone.
        "03:30 PM" ,                                  // Your `String` input text.
        DateTimeFormatter.ofPattern(                  // Define a formatting pattern to match your input text.
            "hh:mm a" ,
            Locale.US                                 // `Locale` determines the human language and cultural norms used in localization. Needed here to translate the `AM` & `PM` value.
        )                                             // Returns a `DateTimeFormatter` object.
    )                                                 // Return a `LocalTime` object.
    .format( DateTimeFormatter.ofPattern("HH:mm") )   // Generate text in a specific format. Returns a `String` object.
;

See this code run live at IdeOne.com.

15:30

See Oracle Tutorial.


Assuming that you use SimpleDateFormat implicitly or explicitly, you need to use H instead of h in the format string.

E.g

HH:mm:ss

instead of

hh:mm:ss


We can solve this by using String Buffer String s;

static String timeConversion(String s) {
   StringBuffer st=new StringBuffer(s);
   for(int i=0;i<=st.length();i++){

       if(st.charAt(0)=='0' && st.charAt(1)=='1' &&st.charAt(8)=='P' ){
        //    if(st.charAt(2)=='1'){
               // st.replace(1,2,"13");
                st.setCharAt(0, '1');
                st.setCharAt(1, '3');
       }else if(st.charAt(0)=='0' && st.charAt(1)=='2' &&st.charAt(8)=='P' ){
        //    if(st.charAt(2)=='1'){
               // st.replace(1,2,"13");
                st.setCharAt(0, '1');
                st.setCharAt(1, '4');
        }else if(st.charAt(0)=='0' && st.charAt(1)=='3' &&st.charAt(8)=='P' ){
        //    if(st.charAt(2)=='1'){
               // st.replace(1,2,"13");
                st.setCharAt(0, '1');
                st.setCharAt(1, '5');
         }else if(st.charAt(0)=='0' && st.charAt(1)=='4' &&st.charAt(8)=='P' ){
        //    if(st.charAt(2)=='1'){
               // st.replace(1,2,"13");
                st.setCharAt(0, '1');
                st.setCharAt(1, '6');
         }else if(st.charAt(0)=='0' && st.charAt(1)=='5' &&st.charAt(8)=='P' ){
        //    if(st.charAt(2)=='1'){
               // st.replace(1,2,"13");
                st.setCharAt(0, '1');
                st.setCharAt(1, '7');
         }else if(st.charAt(0)=='0' && st.charAt(1)=='6' &&st.charAt(8)=='P' ){
        //    if(st.charAt(2)=='1'){
               // st.replace(1,2,"13");
                st.setCharAt(0, '1');
                st.setCharAt(1, '8');
         }else if(st.charAt(0)=='0' && st.charAt(1)=='7' &&st.charAt(8)=='P' ){
        //    if(st.charAt(2)=='1'){
               // st.replace(1,2,"13");
                st.setCharAt(0, '1');
                st.setCharAt(1, '9');
         }else if(st.charAt(0)=='0' && st.charAt(1)=='8' &&st.charAt(8)=='P' ){
        //    if(st.charAt(2)=='1'){
               // st.replace(1,2,"13");
                st.setCharAt(0, '2');
                st.setCharAt(1, '0');
         }else if(st.charAt(0)=='0' && st.charAt(1)=='9' &&st.charAt(8)=='P' ){
        //    if(st.charAt(2)=='1'){
               // st.replace(1,2,"13");
                st.setCharAt(0, '2');
                st.setCharAt(1, '1');
         }else if(st.charAt(0)=='1' && st.charAt(1)=='0' &&st.charAt(8)=='P' ){
        //    if(st.charAt(2)=='1'){
               // st.replace(1,2,"13");
                st.setCharAt(0, '2');
                st.setCharAt(1, '2');
         }else if(st.charAt(0)=='1' && st.charAt(1)=='1' &&st.charAt(8)=='P' ){
        //    if(st.charAt(2)=='1'){
               // st.replace(1,2,"13");
                st.setCharAt(0, '2');
                st.setCharAt(1, '3');
         }else if(st.charAt(0)=='1' && st.charAt(1)=='2' &&st.charAt(8)=='A'  ){
        //    if(st.charAt(2)=='1'){
               // st.replace(1,2,"13");
                st.setCharAt(0, '0');
                st.setCharAt(1, '0');
         }else if(st.charAt(0)=='1' && st.charAt(1)=='2' &&st.charAt(8)=='P'  ){
                st.setCharAt(0, '1');
                st.setCharAt(1, '2');
         }
         if(st.charAt(8)=='P'){
             st.setCharAt(8,' ');

         }else if(st.charAt(8)== 'A'){
             st.setCharAt(8,' ');
         }
         if(st.charAt(9)=='M'){
             st.setCharAt(9,' ');
         }
   }
   String result=st.toString();
   return result;
}

Try This

public static String convertTo24Hour(String Time) {
    DateFormat f1 = new SimpleDateFormat("hh:mm a"); //11:00 pm
    Date d = null;
    try {
        d = f1.parse(Time);
    } catch (ParseException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    DateFormat f2 = new SimpleDateFormat("HH:mm");
    String x = f2.format(d); // "23:00"

    return x;
}

SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm a"); 

provided by Bart Kiers answer should be replaced with somethig like

SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm a",Locale.UK);

   static String timeConversion(String s)
   {
    String s1[]=s.split(":");
    char c[]=s1[2].toCharArray();
    if(s1[2].contains("PM"))
    {
        int n=Integer.parseInt(s1[0]);
        n=n+12;
        return n+":"+s1[1]+":"+c[0]+c[1];
    }
    else``
    return s1[0]+":"+s1[1]+":"+c[0]+c[1];
     }

Using LocalTime in Java 8, LocalTime has many useful methods like getHour() or the getMinute() method,

For example,

LocalTime intime = LocalTime.parse(inputString, DateTimeFormatter.ofPattern("h:m a"));
String outtime = intime.format(DateTimeFormatter.ISO_LOCAL_TIME);

In some cases, First line alone can do the required parsing


12 to 24 hour time conversion and can be reversed if change time formate in output and input SimpleDateFormat class parameter

Test Data Input:

String input = "07:05:45PM"; timeCoversion12to24(input);

output

19:05:45

 public static String timeCoversion12to24(String twelveHoursTime) throws ParseException {

        //Date/time pattern of input date (12 Hours format - hh used for 12 hours)
        DateFormat df = new SimpleDateFormat("hh:mm:ssaa");

        //Date/time pattern of desired output date (24 Hours format HH - Used for 24 hours)
        DateFormat outputformat = new SimpleDateFormat("HH:mm:ss");
        Date date = null;
        String output = null;

        //Returns Date object
        date = df.parse(twelveHoursTime);

        //old date format to new date format
        output = outputformat.format(date);
        System.out.println(output);

        return output;
    }