Conversion from 12 hours time to 24 hours time in java

Question

In my app  I have a requirement to format 12 hours time to 24 hours time  What is the method I have to use   For example  time like 10 30 AM  How can I convert to 24 hours time in java

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Using LocalTime in Java 8  LocalTime has many useful methods like getHour   or the getMinute   method   For example   LocalTime intime   LocalTime parse inputString  DateTimeFormatter ofPattern  h m a     String outtime   intime format DateTimeFormatter ISO LOCAL TIME     In some cases  First line alone can do the required parsing

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Try this to calculate time difference between two times  first it will convert 12 hours time into 24 hours then it will take diff between two times String a    quot 09 06 18 01 55 33 AM quot               String b    quot 07 06 18 05 45 33 PM quot               String    b2   b split  quot   quot                String    a2   a split  quot   quot                SimpleDateFormat displayFormat   new SimpleDateFormat  quot HH mm ss quot                SimpleDateFormat parseFormat   new SimpleDateFormat  quot hh mm ss a quot                String time1   null               String time2   null               if   a contains  quot PM quot    amp  amp  b contains  quot AM quot                                         Date date   parseFormat parse a2 1   quot  PM quot                     time1   displayFormat format date                    time2   b2 1                else if  b contains  quot PM quot    amp  amp  a contains  quot AM quot                      Date date   parseFormat parse a2 1   quot  PM quot                    time1   a2 1                   time2   displayFormat format date                else if  a contains  quot PM quot    amp  amp  b contains  quot PM quot                     Date datea   parseFormat parse a2 1   quot  PM quot                    Date dateb   parseFormat parse b2 1   quot  PM quot                    time1   displayFormat format datea                   time2   displayFormat format dateb                                System out println time1               System out println time2                     SimpleDateFormat format   new SimpleDateFormat  quot HH mm ss quot                Date date1   format parse time1               Date date2   format parse time2               long difference   date2 getTime   - date1 getTime                 System out println difference               System out println  quot Duration   quot  DurationFormatUtils formatDuration difference   quot HH mm quot      For More Details Click Here

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import java text SimpleDateFormat  import java text DateFormat  import java util Date   public class Main      public static void main String    args          try               DateFormat parseFormat   new SimpleDateFormat  dd-MM-yyyy hh mm ss a                String sDate    22-01-2019 9 0 0 PM               Date date   parseFormat parse sDate               SimpleDateFormat displayFormat   new SimpleDateFormat  dd-MM-yyyy HH mm ss                sDate   displayFormat format date               LOGGER info  The required format       sDate                catch  Exception e

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This is the extract of code that I have done       String s  08 10 45       String   s1 s split           int milipmHrs 0      char   arr s1 2  toCharArray        boolean isFound s1 2  contains  PM        if isFound           int pmHrs Integer parseInt s1 0            milipmHrs pmHrs 12          return milipmHrs     s1 1      arr 0  arr 1              else           return s1 0      s1 1      arr 0  arr 1

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Try this   import java text SimpleDateFormat  import java util Date   public class Main      public static void main String    args  throws Exception          SimpleDateFormat displayFormat   new SimpleDateFormat  HH mm           SimpleDateFormat parseFormat   new SimpleDateFormat  hh mm a           Date date   parseFormat parse  10 30 PM           System out println parseFormat format date            displayFormat format date             which produces   10 30 PM   22 30   See  http   download oracle com javase 1 5 0 docs api java text SimpleDateFormat html

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We can solve this by using String Buffer String s   static String timeConversion String s       StringBuffer st new StringBuffer s      for int i 0 i lt  st length   i             if st charAt 0    0   amp  amp  st charAt 1    1   amp  amp st charAt 8    P                   if st charAt 2    1                      st replace 1 2  13                    st setCharAt 0   1                    st setCharAt 1   3            else if st charAt 0    0   amp  amp  st charAt 1    2   amp  amp st charAt 8    P                   if st charAt 2    1                      st replace 1 2  13                    st setCharAt 0   1                    st setCharAt 1   4             else if st charAt 0    0   amp  amp  st charAt 1    3   amp  amp st charAt 8    P                   if st charAt 2    1                      st replace 1 2  13                    st setCharAt 0   1                    st setCharAt 1   5              else if st charAt 0    0   amp  amp  st charAt 1    4   amp  amp st charAt 8    P                   if st charAt 2    1                      st replace 1 2  13                    st setCharAt 0   1                    st setCharAt 1   6              else if st charAt 0    0   amp  amp  st charAt 1    5   amp  amp st charAt 8    P                   if st charAt 2    1                      st replace 1 2  13                    st setCharAt 0   1                    st setCharAt 1   7              else if st charAt 0    0   amp  amp  st charAt 1    6   amp  amp st charAt 8    P                   if st charAt 2    1                      st replace 1 2  13                    st setCharAt 0   1                    st setCharAt 1   8              else if st charAt 0    0   amp  amp  st charAt 1    7   amp  amp st charAt 8    P                   if st charAt 2    1                      st replace 1 2  13                    st setCharAt 0   1                    st setCharAt 1   9              else if st charAt 0    0   amp  amp  st charAt 1    8   amp  amp st charAt 8    P                   if st charAt 2    1                      st replace 1 2  13                    st setCharAt 0   2                    st setCharAt 1   0              else if st charAt 0    0   amp  amp  st charAt 1    9   amp  amp st charAt 8    P                   if st charAt 2    1                      st replace 1 2  13                    st setCharAt 0   2                    st setCharAt 1   1              else if st charAt 0    1   amp  amp  st charAt 1    0   amp  amp st charAt 8    P                   if st charAt 2    1                      st replace 1 2  13                    st setCharAt 0   2                    st setCharAt 1   2              else if st charAt 0    1   amp  amp  st charAt 1    1   amp  amp st charAt 8    P                   if st charAt 2    1                      st replace 1 2  13                    st setCharAt 0   2                    st setCharAt 1   3              else if st charAt 0    1   amp  amp  st charAt 1    2   amp  amp st charAt 8    A                    if st charAt 2    1                      st replace 1 2  13                    st setCharAt 0   0                    st setCharAt 1   0              else if st charAt 0    1   amp  amp  st charAt 1    2   amp  amp st charAt 8    P                      st setCharAt 0   1                    st setCharAt 1   2                        if st charAt 8    P                 st setCharAt 8                  else if st charAt 8     A                 st setCharAt 8                           if st charAt 9    M                 st setCharAt 9                          String result st toString       return result

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Try This  public static String convertTo24Hour String Time        DateFormat f1   new SimpleDateFormat  hh mm a      11 00 pm     Date d   null      try           d   f1 parse Time         catch  ParseException e               TODO Auto-generated catch block         e printStackTrace              DateFormat f2   new SimpleDateFormat  HH mm        String x   f2 format d       23 00       return x

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I have written a simple utility function   public static String convert24HourTimeTo12Hour String timeStr        try           DateFormat inFormat   new SimpleDateFormat   HH mm ss            DateFormat outFormat   new SimpleDateFormat   hh mm a            Date date   inFormat parse timeStr           return outFormat format date        catch  Exception e         return

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12 to 24 hour time conversion and can be reversed if change time formate in output and input SimpleDateFormat class parameter  Test Data Input    String input    07 05 45PM           timeCoversion12to24 input    output  19 05 45   public static String timeCoversion12to24 String twelveHoursTime  throws ParseException              Date time pattern of input date  12 Hours format - hh used for 12 hours          DateFormat df   new SimpleDateFormat  hh mm ssaa               Date time pattern of desired output date  24 Hours format HH - Used for 24 hours          DateFormat outputformat   new SimpleDateFormat  HH mm ss            Date date   null          String output   null             Returns Date object         date   df parse twelveHoursTime              old date format to new date format         output   outputformat format date           System out println output            return output

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Assuming that you use SimpleDateFormat implicitly or explicitly  you need to use H instead of h in the format string   E g  HH mm ss  instead of  hh mm ss

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I was looking for same thing but in number  means from integer xx hour  xx minutes and AM PM to 24 hour format xx hour and xx minutes  so here what i have done    private static final int AM   0  private static final int PM   1           Based on concept  day start from 00 00AM and ends at 11 59PM        afternoon 12 is 12PM  12 xxAM is basically 00 xxAM       param hour12Format       param amPm       return         private int get24FormatHour int hour12Format int amPm       if hour12Format  12  amp  amp  amPm  AM         hour12Format 0            if amPm    PM  amp  amp  hour12Format  12         hour12Format  12            return hour12Format            private int minutesTillMidnight int hour12Format int minutes  int amPm           int hour24Format get24FormatHour hour12Format amPm           System out println  24 Format    hour24Format     minutes            return  hour24Format 60  minutes

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SimpleDateFormat parseFormat   new SimpleDateFormat  hh mm a       provided by Bart Kiers answer  should be replaced with somethig like   SimpleDateFormat parseFormat   new SimpleDateFormat  hh mm a  Locale UK

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java time  In Java 8 and later it could be done in one line using class java time LocalTime    In the formatting pattern  lowercase hh means 12-hour clock while uppercase HH means 24-hour clock   Code example   String result                                            Text representing the value of our date-time object      LocalTime parse                                      Class representing a time-of-day value without a date and without a time zone           03 30 PM                                        Your  String  input text          DateTimeFormatter ofPattern                      Define a formatting pattern to match your input text               hh mm a                Locale US                                     Locale  determines the human language and cultural norms used in localization  Needed here to translate the  AM   amp   PM  value                                                           Returns a  DateTimeFormatter  object                                                           Return a  LocalTime  object       format  DateTimeFormatter ofPattern  HH mm          Generate text in a specific format  Returns a  String  object      See this code run live at IdeOne com      15 30   See Oracle Tutorial

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static String timeConversion String s           String s1   s split           char c   s1 2  toCharArray        if s1 2  contains  PM                  int n Integer parseInt s1 0            n n 12          return n     s1 1      c 0  c 1             else       return s1 0      s1 1      c 0  c 1

[java] Conversion from 12 hours time to 24 hours time in java

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