I have code :
function compute() {
if ($('input[name=type]:checked').val() != undefined) {
var a = $('input[name=service_price]').val();
var b = $('input[name=modem_price]').val();
var total = a + b;
$('#total_price').val(a + b);
}
}
In my code I want sum values of two text inputs and write in a text input that has an id of "total"
My two numbers don't sum together for example :
service_price value = 2000
and modem_price=4000
in this example total input value must be 6000 but it is 20004000
This question is related to
javascript
jquery
input
use parseInt as a = parseInt($('input[name=service_price]').val())
Because at least one value is a string the + operator is being interpreted as a string concatenation operator. The simplest fix for this is to indicate that you intend for the values to be interpreted as numbers.
var total = +a + +b;
and
$('#total_price').val(+a + +b);
Or, better, just pull them out as numbers to begin with:
var a = +$('input[name=service_price]').val();
var b = +$('input[name=modem_price]').val();
var total = a+b;
$('#total_price').val(a+b);
See Mozilla's Unary + documentation.
Note that this is only a good idea if you know the value is going to be a number anyway. If this is user input you must be more careful and probably want to use parseInt
and other validation as other answers suggest.
use parseInt
var total = parseInt(a) + parseInt(b);
$('#total_price').val(total);
<script>_x000D_
$(document).ready(function(){_x000D_
var a =parseInt($("#a").val());_x000D_
var b =parseInt($("#b").val());_x000D_
$("#submit").on("click",function(){_x000D_
var sum = a + b;_x000D_
alert(sum);_x000D_
});_x000D_
});_x000D_
</script>
_x000D_
if in multiple class you want to change additional operation in perticular class that show in below example
$('.like').click(function(){
var like= $(this).text();
$(this).text(+like + +1);
});
Cast them to a Number
$('#total_price').val(Number(a)+Number(b));
But before you do that
if (!isNaN($('input[name=service_price]').val()) {...
Source: Stackoverflow.com