I'm looking for ignore case string comparison in Python.
I tried with:
if line.find('mandy') >= 0:
but no success for ignore case. I need to find a set of words in a given text file. I am reading the file line by line. The word on a line can be mandy, Mandy, MANDY, etc. (I don't want to use toupper/tolower, etc.).
I'm looking for the Python equivalent of the Perl code below.
if ($line=~/^Mandy Pande:/i)
If you don't want to use str.lower(), you can use a regular expression:
import re
if re.search('mandy', 'Mandy Pande', re.IGNORECASE):
# Is True
You can use in operator in conjunction with lower method of strings.
if "mandy" in line.lower():
See this.
In [14]: re.match("mandy", "MaNdY", re.IGNORECASE)
Out[14]: <_sre.SRE_Match object at 0x23a08b8>
you can also use: s.lower() in str.lower()
Try:
if haystackstr.lower().find(needlestr.lower()) != -1:
# True
There's another post here. Try looking at this.
BTW, you're looking for the .lower() method:
string1 = "hi"
string2 = "HI"
if string1.lower() == string2.lower():
print "Equals!"
else:
print "Different!"
import re
if re.search('(?i)Mandy Pande:', line):
...
a = "MandY"
alow = a.lower()
if "mandy" in alow:
print "true"
work around
Source: Stackoverflow.com