I got an run time exception in my program while I am reading a file through a Scanner.
java.util.NoSuchElementException: No line found
at java.util.Scanner.nextLine(Unknown Source)
at Day1.ReadFile.read(ReadFile.java:49)
at Day1.ParseTree.main(ParseTree.java:17)
My code is:
while((str=sc.nextLine())!=null){
i=0;
if(str.equals("Locations"))
{
size=4;
t=3;
str=sc.nextLine();
str=sc.nextLine();
}
if(str.equals("Professions"))
{
size=3;
t=2;
str=sc.nextLine();
str=sc.nextLine();
}
if(str.equals("Individuals"))
{
size=4;
t=4;
str=sc.nextLine();
str=sc.nextLine();
}
int j=0;
String loc[]=new String[size];
while(j<size){
beg=0;
end=str.indexOf(',');
if(end!=-1){
tmp=str.substring(beg, end);
beg=end+2;
}
if(end==-1)
{
tmp=str.substring(beg);
}
if(beg<str.length())
str=str.substring(beg);
loc[i]=tmp;
i++;
if(i==size ){
if(t==3)
{
location.add(loc);
}
if(t==2)
{
profession.add(loc);
}
if(t==4)
{
individual.add(loc);
}
i=0;
}
j++;
System.out.print("\n");
}
This question is related to
java
java.util.scanner
Need to use top comment but also pay attention to nextLine(). To eliminate this error only call
sc.nextLine()
Once from inside your while loop
while (sc.hasNextLine()) {sc.nextLine()...}
You are using while to look ahead only 1 line. Then using sc.nextLine() to read 2 lines ahead of the single line you asked the while loop to look ahead.
Also change the multiple IF statements to IF, ELSE to avoid reading more than one line also.
You're calling nextLine()
and it's throwing an exception when there's no line, exactly as the javadoc describes. It will never return null
http://download.oracle.com/javase/1,5.0/docs/api/java/util/Scanner.html
Your real problem is that you are calling "sc.nextLine()" MORE TIMES than the number of lines.
For example, if you have only TEN input lines, then you can ONLY call "sc.nextLine()" TEN times.
Every time you call "sc.nextLine()", one input line will be consumed. If you call "sc.nextLine()" MORE TIMES than the number of lines, you will have an exception called
"java.util.NoSuchElementException: No line found".
If you have to call "sc.nextLine()" n times, then you have to have at least n lines.
Try to change your code to match the number of times you call "sc.nextLine()" with the number of lines, and I guarantee that your problem will be solved.
For whatever reason, the Scanner class also issues this same exception if it encounters special characters it cannot read. Beyond using the hasNextLine()
method before each call to nextLine()
, make sure the correct encoding is passed to the Scanner
constructor, e.g.:
Scanner scanner = new Scanner(new FileInputStream(filePath), "UTF-8");
I also encounter with that problem. In my case the problem was that i closed the scanner inside one of the funcs..
public class Main _x000D_
{_x000D_
public static void main(String[] args) _x000D_
{_x000D_
Scanner menu = new Scanner(System.in);_x000D_
boolean exit = new Boolean(false);_x000D_
while(!exit){_x000D_
String choose = menu.nextLine();_x000D_
Part1 t=new Part1()_x000D_
t.start();_x000D_
System.out.println("Noooooo Come back!!!"+choose);_x000D_
}_x000D_
menu.close();_x000D_
}_x000D_
}_x000D_
_x000D_
public class Part1 extends Thread _x000D_
{_x000D_
public void run()_x000D_
{ _x000D_
Scanner s = new Scanner(System.in);_x000D_
String st = s.nextLine();_x000D_
System.out.print("bllaaaaaaa\n"+st);_x000D_
s.close();_x000D_
}_x000D_
}_x000D_
_x000D_
_x000D_
The code above made the same exaption, the solution was to close the scanner only once at the main.
Source: Stackoverflow.com