[linux] Highlight text similar to grep, but don't filter out text

EDIT:

This works with OS X Mountain Lion's grep:

grep --color -E 'pattern1|pattern2|$'

This is better than '^|pattern1|pattern2' because the ^ part of the alternation matches at the beginning of the line whereas the $ matches at the end of the line. Some regular expression engines won't highlight pattern1 or pattern2 because ^ already matched and the engine is eager.

Something similar happens for 'pattern1|pattern2|' because the regex engine notices the empty alternation at the end of the pattern string matches the beginning of the subject string.

[1]: http://www.regular-expressions.info/engine.html

FIRST EDIT:

I ended up using perl:

perl -pe 's:pattern:\033[31;1m$&\033[30;0m:g'

This assumes you have an ANSI-compatible terminal.

ORIGINAL ANSWER:

If you're stuck with a strange grep, this might work:

grep -E --color=always -A500 -B500 'pattern1|pattern2' | grep -v '^--'

Adjust the numbers to get all the lines you want.

The second grep just removes extraneous -- lines inserted by the BSD-style grep on Mac OS X Mountain Lion, even when the context of consecutive matches overlap.

I thought GNU grep omitted the -- lines when context overlaps, but it's been awhile so maybe I remember wrong.

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