How to create a Restful web service with input parameters

Question

I am creating restful web service and i wanted to know how do we create a service with input parameters and also how to invoke it from a web browser   For example   Path   todo   public class TodoResource          This method is called if XMLis request      PUT      Produces   MediaType APPLICATION XML MediaType APPLICATION JSON       public Todo getXML             Todo todo   new Todo            todo setSummary  This is my first todo            todo setDescription  This is my first todo            return todo          and i can invoke it using  http   localhost 8088 JerseyJAXB rest todo  and I want to create a method like    Path   todo       public class TodoResource              This method is called if XMLis request          PUT          Produces   MediaType APPLICATION XML MediaType APPLICATION JSON           public Todo getXML String x  String y                Todo todo   new Todo                todo setSummary x               todo setDescription y               return todo              In case of soap based web services i would invoke it like this  http   localhost 8088 JerseyJAXB rest todo x abc amp y pqr  but I want to know how to invoke it using rest and also can I pass the parameters as I am doing in the above example when I use rest and jersey

User · Answer

another way to do is get the UriInfo instead of all the QueryParam

Then you will be able to get the queryParam as per needed in your code

@GET
@Path("/query")
public Response getUsers(@Context UriInfo info) {

    String param_1 = info.getQueryParameters().getFirst("param_1");
    String param_2 = info.getQueryParameters().getFirst("param_2");


    return Response ;

}

User · Answer

You can  Try something like this    Path   todo  varX   varY     Produces   application xml    application json    public Todo whatEverNameYouLike  PathParam  varX   String varX       PathParam  varY   String varY            Todo todo   new Todo            todo setSummary varX           todo setDescription varY           return todo      Then call your service with this URL  http   localhost 8088 JerseyJAXB rest todo summary description

User · Answer

If you want query parameters  you use  QueryParam   public Todo getXML  QueryParam  summary   String x                       QueryParam  description   String y    But you won t be able to send a PUT from a plain web browser  today   If you type in the URL directly  it will be a GET    Philosophically  this looks like it should be a POST  though  In REST  you typically either POST to a common resource   todo  where that resource creates and returns a new resource  or you PUT to a specifically-identified resource  like  todo  lt id gt   for creation and or update

User · Answer

Be careful  For this you need  GET  not  PUT

User · Answer

You can try this     put  parameters as       http   localhost 8080 WebApplication11 webresources generic getText arg1 hello     in your browser     package newpackage   import javax ws rs core Context  import javax ws rs core UriInfo  import javax ws rs PathParam  import javax ws rs Produces  import javax ws rs Consumes  import javax ws rs DefaultValue    import javax ws rs GET  import javax ws rs Path  import javax ws rs PUT  import javax ws rs QueryParam    Path  generic   public class GenericResource         Context     private UriInfo context                  Creates a new instance of GenericResource             public GenericResource                           Retrieves representation of an instance of newpackage GenericResource          return an instance of java lang String              GET      Produces  text plain        Consumes  text plain        Path  getText        public String getText  QueryParam  arg1                DefaultValue     String arg1            return  arg1            PUT      Consumes  text plain       public void putText String content

[java] How to create a Restful web service with input parameters?

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