How can I truncate a double to only two decimal places in Java

Question

For example I have the variable 3 545555555  which I would want to truncate to just 3 54

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double value   3 4555        String value1    String format  quot    3f quot   value          String value2   value1 substring 0  value1 length   - 1         System out println value2                  double doublevalue  Double valueOf value2         System out println doublevalue

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If you want that for display purposes  use java text DecimalFormat    new DecimalFormat         format dblVar     If you need it for calculations  use java lang Math    Math floor value   100    100

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This worked for me   double input   104 8695412    For example  long roundedInt   Math round input   100   double result    double  roundedInt 100     result    104 87   I personally like this version because it actually performs the rounding numerically  rather than by converting it to a String  or similar  and then formatting it

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Bit Old Forum  None of the above answer worked for both positive and negative values   I mean for the calculation and just to do truncate without Rounding   From the How to round a number to n decimal places in Java link   private static BigDecimal truncateDecimal double x int numberofDecimals        if   x  gt  0            return new BigDecimal String valueOf x   setScale numberofDecimals  BigDecimal ROUND FLOOR         else           return new BigDecimal String valueOf x   setScale numberofDecimals  BigDecimal ROUND CEILING             This method worked fine for me    System out println truncateDecimal 0  2        System out println truncateDecimal 9 62  2        System out println truncateDecimal 9 621  2        System out println truncateDecimal 9 629  2        System out println truncateDecimal 9 625  2        System out println truncateDecimal 9 999  2        System out println truncateDecimal -9 999  2        System out println truncateDecimal -9 0  2      Results    0 00 9 62 9 62 9 62 9 62 9 99 -9 99 -9 00

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A quick check is to use the Math floor method   I created a method to check a double for two or less decimal places below   public boolean checkTwoDecimalPlaces double valueToCheck            Get two decimal value of input valueToCheck      double twoDecimalValue   Math floor valueToCheck   100    100          Return true if the twoDecimalValue is the same as valueToCheck else return false     return twoDecimalValue    valueToCheck

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Formating as a string and converting back to double i think will give you the result you want   The double value will not be round    floor   or ceil     A quick fix for it could be    String sValue    String  String format    2f   oldValue    Double newValue   Double parseDouble sValue     You can use the sValue for display purposes or the newValue for calculation

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If  for whatever reason  you don t want to use a BigDecimal you can cast your double to an int to truncate it    If you want to truncate to the Ones place    simply cast to int   To the Tenths place    multiply by ten cast to int cast back to double and divide by ten    Hundreths place   multiply and divide by 100 etc    Example   static double truncateTo  double unroundedNumber  int decimalPlaces        int truncatedNumberInt    int   unroundedNumber   Math pow  10  decimalPlaces          double truncatedNumber    double   truncatedNumberInt   Math pow  10  decimalPlaces          return truncatedNumber      In this example  decimalPlaces would be the number of places PAST the ones place you wish to go  so 1 would round to the tenths place  2 to the hundredths  and so on  0 rounds to the ones place  and negative one to the tens  etc

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You can use NumberFormat Class object to accomplish the task      Creating number format object to set 2 places after decimal point NumberFormat nf   NumberFormat getInstance    nf setMaximumFractionDigits 2               nf setGroupingUsed false    System out println nf format precision      Assuming precision is a double type variable

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Here is the method I use   double a 3 545555555     just assigning your decimal to a variable a a 100                  this sets a to 354 555555 a Math floor a           this sets a to 354 a a 100                  this sets a to 3 54 and thus removing all your 5 s   This can also be done   a Math floor a 100    100

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if double v is 3 545555555 String string v  String valueOf double v   int pointer pos   average indexOf        we find the position of     string v substring 0  pointer pos 2      in this way we get the double with only 2 decimal in string form double v   Double valueOf string v    well this is the final result   well this might be a little awkward  but i think it can solve your problem

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Note first that a double is a binary fraction and does not really have decimal places   If you need decimal places  use a BigDecimal  which has a setScale   method for truncation  or use DecimalFormat to get a String

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I have a slightly modified version of Mani s   private static BigDecimal truncateDecimal final double x  final int numberofDecimals        return new BigDecimal String valueOf x   setScale numberofDecimals  BigDecimal ROUND DOWN      public static void main String   args        System out println truncateDecimal 0  2        System out println truncateDecimal 9 62  2        System out println truncateDecimal 9 621  2        System out println truncateDecimal 9 629  2        System out println truncateDecimal 9 625  2        System out println truncateDecimal 9 999  2        System out println truncateDecimal 3 545555555  2         System out println truncateDecimal 9 0  2        System out println truncateDecimal -9 62  2        System out println truncateDecimal -9 621  2        System out println truncateDecimal -9 629  2        System out println truncateDecimal -9 625  2        System out println truncateDecimal -9 999  2        System out println truncateDecimal -9 0  2        System out println truncateDecimal -3 545555555  2         Output   0 00 9 62 9 62 9 62 9 62 9 99 9 00 3 54 -9 62 -9 62 -9 62 -9 62 -9 99 -9 00 -3 54

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Maybe following    double roundTwoDecimals double d           DecimalFormat twoDForm   new DecimalFormat                 return Double valueOf twoDForm format d

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DecimalFormat df   new DecimalFormat fmt   df setRoundingMode RoundingMode DOWN   s   df format d     Check available RoundingMode and DecimalFormat

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3 545555555 to get 3 54  Try Following for this       DecimalFormat df   new DecimalFormat               df setRoundingMode RoundingMode FLOOR        double result   new Double df format 3 545555555     This will give  3 54

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Maybe Math floor value   100    100  Beware that the values like 3 54 may be not exactly represented with a double

[java] How can I truncate a double to only two decimal places in Java?

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