os path dirname file returns empty

Question

I want to get the path of the current directory under which a  py file is executed   For example a simple file D  test py with code   import os  print os getcwd   print os path basename   file    print os path abspath   file    print os path dirname   file      It is weird that the output is   D   test py D  test py EMPTY   I am expecting the same results from the getcwd   and path dirname     Given os path abspath   os path dirname   os path basename  why   os path dirname   file      returns empty

User · Answer

os path split os path realpath   file     0    os path realpath   file   return the abspath of the current script      os path split abspath  0  return the current dir

User · Answer

Because os path abspath   os path dirname   os path basename does not hold   we rather have  os path dirname filename    os path basename filename     filename   Both dirname   and basename   only split the passed filename into components without taking into account the current directory   If you want to also consider the current directory  you have to do so explicitly   To get the dirname of the absolute path  use  os path dirname os path abspath   file

User · Answer

print os path join os path dirname   file         You can also use this way

User · Answer

import os path  dirname   os path dirname   file    or

User · Answer

can be used also like that   dirname dirname abspath   file

[python] os.path.dirname(file) returns empty

Examples related to python

[python] os.path.dirname(__file__) returns empty

Examples related to python

[python] os.path.dirname(file) returns empty