Check if string is upper lower or mixed case in Python

Question

I want to classify a list of string in Python depending on whether they are upper case  lower case  or mixed case  How can I do this

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I want to give a shoutout for using re module for this  Specially in the case of case sensitivity    We use the option re IGNORECASE while compiling the regex for use of in production environments with large amounts of data    gt  gt  gt  import re  gt  gt  gt  m     isalnum   isalpha    isdigit    islower    isspace    istitle    isupper    ISALNUM    ISALPHA    ISDIGIT    ISLOWER    ISSPACE    ISTITLE    ISUPPER    gt  gt  gt   gt  gt  gt   gt  gt  gt  pattern   re compile  is    gt  gt  gt   gt  gt  gt   word for word in m if pattern match word     isalnum    isalpha    isdigit    islower    isspace    istitle    isupper     However try to always use the in operator for string comparison as detailed in this post   faster-operation-re-match-or-str  Also detailed in the one of the best books to start learning python with  idiomatic-python

User · Answer

There are a number of  is methods  on strings  islower   and isupper   should meet your needs    gt  gt  gt   hello  islower   True   gt  gt  gt   m for m in dir str  if m startswith  is      isalnum    isalpha    isdigit    islower    isspace    istitle    isupper     Here s an example of how to use those methods to classify a list of strings    gt  gt  gt  words     The    quick    BROWN    Fox    jumped    OVER    the    Lazy    DOG    gt  gt  gt   word for word in words if word islower      quick    jumped    the    gt  gt  gt   word for word in words if word isupper      BROWN    OVER    DOG    gt  gt  gt   word for word in words if not word islower   and not word isupper      The    Fox    Lazy

[python] Check if string is upper, lower, or mixed case in Python

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