Removing character in list of strings

Question

If I have a list of strings such as      aaaa8     bb8     ccc8     dddddd8         What should I do in order to get rid of all the 8s in each string  I tried using strip or replace in a for loop but it doesn t work like it would in a normal string  that not in a list   Does anyone have a suggestion

User · Answer

mylist      aaaa8     bb8     ccc8     dddddd8    print mylist j 0 for i in mylist      mylist j  i rstrip  8       j  1 print mylist

User · Answer

Here s a short one-liner using regular expressions   print  re compile r 8   sub     m  for m in mylist    If we separate the regex operations and improve the namings   pattern   re compile r 8     Create the regular expression to match res    pattern sub     match  for match in mylist    Remove match on each element print res

User · Answer

A faster way is to join the list  replace 8 and split the new string   mylist      aaaa8     bb8     ccc8     dddddd8    mylist       join mylist  replace  8      split   print mylist

User · Answer

Beside using loop and for comprehension  you could also use map  lst      aaaa8     bb8     ccc8     dddddd8    mylst   map lambda each each strip  8    lst  print mylst

User · Answer

lst      aaaa8     bb8     ccc8     dddddd8        msg   filter lambda x   x     8   lst   print msg   EDIT  For anyone who came across this post  just for understanding the above removes any elements from the list which are equal to 8   Supposing we use the above example the first element   aaaaa8   would not be equal to 8 and so it would be dropped   To make this  kinda work   with how the intent of the question was we could perform something similar to this   msg   filter lambda x  x     8   map lambda y  list y   lst      I am not in an interpreter at the moment so of course mileage may vary  we may have to index so we do list y 0   would be the only modification to the above for this explanation purposes    What this does is split each element of list up into an array of characters so   aaaa8   would become   a    a    a    a    8     This would result in a data type that looks like this  msg      a    a    a    a      b    b        So finally to wrap that up we would have to map it to bring them all back into the same type roughly  msg   list map lambda q     join q   filter lambda x  x     8   map lambda y  list y 0    lst       I would absolutely not recommend it  but if you were really wanting to play with map and filter  that would be how I think you could do it with a single line

User · Answer

Try this   lst      aaaa8     bb8     ccc8     dddddd8    print  s strip  8   for s in lst     remove the 8 from the string borders print  s replace  8       for s in lst     remove all the 8s

[python] Removing character in list of strings

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