There is doing XML reading right, or doing the dodgy just to get by. Doing it right would be using proper document parsing.
Or... dodgy would be using custom text parsing with either wisuzu's response or using regular expressions with matchers.
You could also use tools provided by the base JRE:
String msg = "<message>HELLO!</message>";
DocumentBuilder newDocumentBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
Document parse = newDocumentBuilder.parse(new ByteArrayInputStream(msg.getBytes()));
System.out.println(parse.getFirstChild().getTextContent());
I think you would be look at String class, there are multiple ways to do it. What about substring(int,int)
and indexOf(int)
lastIndexOf(int)
?
You could do this with JAXB (an implementation is included in Java SE 6).
import java.io.StringReader;
import javax.xml.bind.*;
import javax.xml.transform.stream.StreamSource;
public class Demo {
public static void main(String[] args) throws Exception {
String xmlString = "<message>HELLO!</message> ";
JAXBContext jc = JAXBContext.newInstance(String.class);
Unmarshaller unmarshaller = jc.createUnmarshaller();
StreamSource xmlSource = new StreamSource(new StringReader(xmlString));
JAXBElement<String> je = unmarshaller.unmarshal(xmlSource, String.class);
System.out.println(je.getValue());
}
}
Output
HELLO!
One of the above answer states to convert XML String to bytes which is not needed. Instead you can can use InputSource
and supply it with StringReader
.
String xmlStr = "<message>HELLO!</message>";
DocumentBuilder db = DocumentBuilderFactory.newInstance().newDocumentBuilder();
Document doc = db.parse(new InputSource(new StringReader(xmlStr)));
System.out.println(doc.getFirstChild().getNodeValue());
Source: Stackoverflow.com