[node.js] Why is __dirname not defined in node REPL?

From the node manual I see that I can get the directory of a file with __dirname, but from the REPL this seems to be undefined. Is this a misunderstanding on my side or where is the error?

$ node
> console.log(__dirname)
ReferenceError: __dirname is not defined
    at repl:1:14
    at REPLServer.eval (repl.js:80:21)
    at Interface.<anonymous> (repl.js:182:12)
    at Interface.emit (events.js:67:17)
    at Interface._onLine (readline.js:162:10)
    at Interface._line (readline.js:426:8)
    at Interface._ttyWrite (readline.js:603:14)
    at ReadStream.<anonymous> (readline.js:82:12)
    at ReadStream.emit (events.js:88:20)
    at ReadStream._emitKey (tty.js:320:10)

If you are using Node.js modules, __dirname and __filename don't exist.

From the Node.js documentation:

No require, exports, module.exports, __filename, __dirname

These CommonJS variables are not available in ES modules.

require can be imported into an ES module using module.createRequire().

Equivalents of __filename and __dirname can be created inside of each file via import.meta.url:

import { fileURLToPath } from 'url';
import { dirname } from 'path';

const __filename = fileURLToPath(import.meta.url);
const __dirname = dirname(__filename);

https://nodejs.org/docs/latest-v15.x/api/esm.html#esm_no_filename_or_dirname

Building on the existing answers here, you could define this in your REPL:

__dirname = path.resolve(path.dirname(''));

Or:

__dirname = path.resolve();

If no path segments are passed, path.resolve() will return the absolute path of the current working directory.

Or @Jthorpe's alternatives:

__dirname = process.cwd();
__dirname = fs.realpathSync('.');
__dirname = process.env.PWD

I was also trying to join my path using path.join(__dirname, 'access.log') but it was throwing the same error.

Here is how I fixed it:

I first imported the path package and declared a variable named __dirname, then called the resolve path method.

In CommonJS

var path = require("path");

var __dirname = path.resolve();

In ES6+

import path  from 'path';

const __dirname = path.resolve();

Happy coding.......

Seems like you could also do this:

__dirname=fs.realpathSync('.');

of course, dont forget fs=require('fs')

(it's not really global in node scripts exactly, its just defined on the module level)

If you got node __dirname not defined with node --experimental-modules, you can do :

const __dirname = path.dirname(import.meta.url)
                      .replace(/^file:\/\/\//, '') // can be usefull

Because othe example, work only with current/pwd directory not other directory.

Though its not the solution to this problem I would like to add it as it may help others.

You should have two underscores before dirname, not one underscore (__dirname not _dirname).

NodeJS Docs

In ES6 use:

import path from 'path';
const __dirname = path.resolve();

also available when node is called with --experimental-modules

I was running a script from batch file as SYSTEM user and all variables like process.cwd() , path.resolve() and all other methods would give me path to C:\Windows\System32 folder instead of actual path. During experiments I noticed that when an error is thrown the stack contains a true path to the node file.

Here's a very hacky way to get true path by triggering an error and extracting path from e.stack. Do not use.

// this should be the name of currently executed file
const currentFilename = 'index.js';

function veryHackyGetFolder() {
  try {
    throw new Error();
  } catch(e) {
    const fullMsg = e.stack.toString();
    const beginning = fullMsg.indexOf('file:///') + 8;
    const end = fullMsg.indexOf('\/' + currentFilename);
    const dir = fullMsg.substr(beginning, end - beginning).replace(/\//g, '\\');
    return dir;
  }
}

Usage

const dir = veryHackyGetFolder();

As @qiao said, you can't use __dirname in the node repl. However, if you need need this value in the console, you can use path.resolve() or path.dirname(). Although, path.dirname() will just give you a "." so, probably not that helpful. Be sure to require('path').