[python] How do I detect the Python version at runtime?

I have a Python file which might have to support Python versions < 3.x and >= 3.x. Is there a way to introspect the Python runtime to know the version which it is running (for example, 2.6 or 3.2.x)?

This question is related to python

The answer is


Try this code, this should work:

import platform
print(platform.python_version())

Just in case you want to see all of the gory details in human readable form, you can use:

import platform;

print(platform.sys.version);

Output for my system:

3.6.5 |Anaconda, Inc.| (default, Apr 29 2018, 16:14:56) 
[GCC 7.2.0]

Something very detailed but machine parsable would be to get the version_info object from platform.sys, instead, and then use its properties to take a predetermined course of action. For example:

import platform;

print(platform.sys.version_info)

Output on my system:

sys.version_info(major=3, minor=6, micro=5, releaselevel='final', serial=0)

Since all you are interested in is whether you have Python 2 or 3, a bit hackish but definitely the simplest and 100% working way of doing that would be as follows: python python_version_major = 3/2*2 The only drawback of this is that when there is Python 4, it will probably still give you 3.


To make the scripts compatible with Python2 and 3 i use :

from sys import version_info
if version_info[0] < 3:
    from __future__ import print_function

Here's some code I use with sys.version_info to check the Python installation:

def check_installation(rv):
    current_version = sys.version_info
    if current_version[0] == rv[0] and current_version[1] >= rv[1]:
        pass
    else:
        sys.stderr.write( "[%s] - Error: Your Python interpreter must be %d.%d or greater (within major version %d)\n" % (sys.argv[0], rv[0], rv[1], rv[0]) )
        sys.exit(-1)
    return 0

...

# Calling the 'check_installation' function checks if Python is >= 2.7 and < 3
required_version = (2,7)
check_installation(required_version)

Per sys.hexversion and API and ABI Versioning:

import sys
if sys.hexversion >= 0x3000000:
    print('Python 3.x hexversion %s is in use.' % hex(sys.hexversion))

Version check example below.

Note that I do not stop the execution, this snippet just:
- do nothing if exact version matches
- write INFO if revision (last number) is different
- write WARN if any of major+minor are different

import sys
import warnings

def checkVersion():
    # Checking Python version:
    expect_major = 2
    expect_minor = 7
    expect_rev = 14
    if sys.version_info[:3] != (expect_major, expect_minor, expect_rev):
        print("INFO: Script developed and tested with Python " + str(expect_major) + "." + str(expect_minor) + "." + str(expect_rev))
        current_version = str(sys.version_info[0])+"."+str(sys.version_info[1])+"."+str(sys.version_info[2])
        if sys.version_info[:2] != (expect_major, expect_minor):
            warnings.warn("Current Python version was unexpected: Python " + current_version)
        else:
            print("      Current version is different: Python " + current_version)

The best solution depends on how much code is incompatible. If there are a lot of places you need to support Python 2 and 3, six is the compatibility module. six.PY2 and six.PY3 are two booleans if you want to check the version.

However, a better solution than using a lot of if statements is to use six compatibility functions if possible. Hypothetically, if Python 3000 has a new syntax for next, someone could update six so your old code would still work.

import six

#OK
if six.PY2:
  x = it.next() # Python 2 syntax
else:
  x = next(it) # Python 3 syntax

#Better
x = six.next(it)

http://pythonhosted.org/six/

Cheers