[r] Extract Month and Year From Date in R

I have tried a number of methods to no avail. I have data in terms of a date (YYYY-MM-DD) and am trying to get in terms of just the month and year, such as: MM-YYYY or YYYY-MM.

Ultimately, I would like it to look like this:

ID    Date         Month_Yr
1     2004-02-06   2004-02
2     2006-03-14   2006-03
3     2007-07-16   2007-07
...   ...          ...

I am doing this in hopes of plotting money earned on average in a month, from a number of orders, over a period of time. Any help, or a push in the right direction would be much appreciated.

Use substring?

d = "2004-02-06"
substr(d,0,7)
>"2004-02"

The zoo package has the function of as.yearmon can help to convert.

require(zoo)

df$ym<-as.yearmon(df$date, "%Y %m")

Here's another solution using a package solely dedicated to working with dates and times in R:

library(tidyverse)
library(lubridate)

(df <- tibble(ID = 1:3, Date = c("2004-02-06" , "2006-03-14", "2007-07-16")))
#> # A tibble: 3 x 2
#>      ID Date      
#>   <int> <chr>     
#> 1     1 2004-02-06
#> 2     2 2006-03-14
#> 3     3 2007-07-16

df %>%
  mutate(
    Date = ymd(Date),
    Month_Yr = format_ISO8601(Date, precision = "ym")
  )
#> # A tibble: 3 x 3
#>      ID Date       Month_Yr
#>   <int> <date>     <chr>   
#> 1     1 2004-02-06 2004-02 
#> 2     2 2006-03-14 2006-03 
#> 3     3 2007-07-16 2007-07

^{Created on 2020-09-01 by the reprex package (v0.3.0)}

The data.table package introduced the IDate class some time ago and zoo-package-like functions to retrieve months, days, etc (Check ?IDate). so, you can extract the desired info now in the following ways:

require(data.table)
df <- data.frame(id = 1:3,
                 date = c("2004-02-06" , "2006-03-14" , "2007-07-16"))
setDT(df)
df[ , date := as.IDate(date) ] # instead of as.Date()
df[ , yrmn := paste0(year(date), '-', month(date)) ]
df[ , yrmn2 := format(date, '%Y-%m') ]