Using s in C correctly - very basic level

Question

I know that  s is a string of characters  but I don t know how to use it  Can anyone provide me a very basic example of how its used and how its different from char       edited   i m 2 weeks into this course  it s my first time programming  I m not allowed to use material that hasn t been taught yet on the assignments  so that s why I asked  I have a few books on C and have googled but still wasn t sure  so I asked   thanks for all the down-votes  All the examples given below use arrays which hasn t been taught yet  so I m assuming I can t use  s yet either  Thanks

User · Answer

s is the representation of an array of char  char string 10     here is a array of chars  they max length is 10  char character     just a char 1 letter from the ascii map  character    a      assign  a  to character printf  character  c    a     we will display  a  to stout   so string is an array of char we can assign multiple character per space of memory  string 0   h   string 1   e   string 2   l   string 3   l   string 4   o   string 5   char  0   asigning the last element of the  word  a mark so the string ends   this assignation  can be done at initialization like     char word  this is a word     the word array of chars got this string now and is statically defined  toy can also assign values to the array of chars assigning it with functions like strcpy   strcpy string  hello       this do the same as the example and automatically add the  char  0 at the end  so if you print it with  S     printf  my string  s  string    and how string is a array we can just display part of it                             the array    one char printf  first letter of wrd  s     is      c   string string 1

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Here goes   char str      This is the end   char input 100    printf   s n   str   printf   c n    str    scanf   99s   input

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void myfunc void        char  text    Hello World       char  aLetter    C        printf   s n   text       printf   c n   aLetter

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For both  printf and  scanf   s expects the corresponding argument to be of type char    and for scanf  it had better point to a writable buffer  i e   not a string literal      char  str constant    I point to a string literal   char str buf      I am an array of char initialized with a string literal    printf  string literal    s n    I am a string literal    printf  str constant    s n   str constant   printf  str buf    s n   str buf    scanf   55s   str buf     Using  s in scanf without an explcit field width opens the same buffer overflow exploit that gets did  namely  if there are more characters in the input stream than the target buffer is sized to hold  scanf will happily write those extra characters to memory outside the buffer  potentially clobbering something important   Unfortunately  unlike in printf  you can t supply the field with as a run time argument   printf    s n   field width  string     One option is to build the format string dynamically   char fmt 10   sprintf fmt      lus    unsigned long   sizeof str buf  - 1       scanf fmt  target buffer      fmt     55s    EDIT  Using scanf with the  s conversion specifier will stop scanning at the first whitespace character  for example  if your input stream looks like   This is a test    then scanf   55s   str buf  will read and assign  This  to str buf   Note that the field with specifier doesn t make a difference in this case

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s will get all the values until it gets NULL i e    0    char str1      This is the end 0   printf   s  str1     will give  This is the end  char str2      this is 0 the end 0   printf   s  str2     will give  this is

[c] Using %s in C correctly - very basic level

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