How to convert an int value to string in Go

Question

i    123 s    string i     s is  E   but what I want is  123   Please tell me how can I get  123    And in Java  I can do in this way    String s    ab     c      s is  abc    how can I concat two strings in Go

User · Answer

fmt Sprintf   v  value     If you know the specific type of value use the corresponding formatter for example  d for int   More info - fmt

User · Answer

Use the strconv package s Itoa function   For example   package main  import        strconv       fmt     func main         t    strconv Itoa 123      fmt Println t      You can concat strings simply by   ing them  or by using the Join function of the strings package

User · Answer

package main  import        fmt        strconv     func main      First question  how to get int string       intValue    123        keeping it in separate variable        strValue    strconv Itoa intValue       fmt Println strValue     Second question  how to concat two strings       firstStr     ab      secondStr     c      s    firstStr   secondStr     fmt Println s

User · Answer

In this case both strconv and fmt Sprintf do the same job but using the strconv package s Itoa function is the best choice  because fmt Sprintf allocate one more object during conversion     check the benchmark here  https   gist github com evalphobia caee1602969a640a4530  see https   play golang org p hlaz rMa0D for example

User · Answer

ok most of them have shown you something good  Let me give you this      ToString Change arg to string func ToString arg interface    timeFormat    string  string       if len timeFormat   gt  1           log SetFlags log Llongfile   log LstdFlags          log Println errors New fmt Sprintf  timeFormat s length should be one               var tmp   reflect Indirect reflect ValueOf arg   Interface       switch v    tmp  type        case int          return strconv Itoa v      case int8          return strconv FormatInt int64 v   10      case int16          return strconv FormatInt int64 v   10      case int32          return strconv FormatInt int64 v   10      case int64          return strconv FormatInt v  10      case string          return v     case float32          return strconv FormatFloat float64 v    f   -1  32      case float64          return strconv FormatFloat v   f   -1  64      case time Time          if len timeFormat     1               return v Format timeFormat 0                     return v Format  2006-01-02 15 04 05       case jsoncrack Time          if len timeFormat     1               return v Time   Format timeFormat 0                     return v Time   Format  2006-01-02 15 04 05       case fmt Stringer          return v String       case reflect Value          return ToString v Interface    timeFormat         default          return

User · Answer

You can use fmt Sprintf or strconv FormatFloat For example package main  import        quot fmt quot     func main         val    14 7     s    fmt Sprintf  quot  f quot   val      fmt Println s

User · Answer

Converting int64   n    int64 32  str    strconv FormatInt n  10   fmt Println str     Prints  32

User · Answer

It is interesting to note that strconv Itoa is shorthand for   func FormatInt i int64  base int  string   with base 10  For Example   strconv Itoa 123    is equivalent to  strconv FormatInt int64 123   10

User · Answer

fmt Sprintf  strconv Itoa and strconv FormatInt will do the job  But Sprintf will use the package reflect  and it will allocate one more object   so it s not an efficient choice

[string] How to convert an int value to string in Go?

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