You do say that the comparison is for sorting purposes. Then I suggest instead:
"a".localeCompare("b");
It returns -1
since "a" < "b"
, 1
or 0
otherwise, like you need for Array.prototype.sort()
Keep in mind that sorting is locale dependent. E.g. in German, ä
is a variant of a
, so "ä".localeCompare("b", "de-DE")
returns -1
. In Swedish, ä
is one of the last letters in the alphabet, so "ä".localeCompare("b", "se-SE")
returns 1
.
Without the second parameter to localeCompare
, the browser's locale is used. Which in my experience is never what I want, because then it'll sort differently than the server, which has a fixed locale for all users.